Question

我有一些json，我想解析为pojo

{
  "groups": [
    {
      "g1": [
        1,2,5,6,7
      ]
    },
    {
      "g2": [
        2,3,48,79
      ]
    }
  ]
}

当然，"g1"和"g1"是标识符，所以我想象pojos会像......

class Container {
    List<Group> groups;
}

class Group {
    String id;
    List<Integer> values;
}

所以归结为这个问题：如何使用jackson将json属性映射到pojo？

Answer 1

可以使用添加了JsonDeserialize注释的自定义反序列化器来解析这种结构。

的POJO

public static class Container {
    private List<Group> groups;
    public List<Group> getGroups() {
        return groups;
    }
    public void setGroups(List<Group> groups) {
        this.groups = groups;
    }
    @Override
    public String toString() {
        return String.format("Container [groups=%s]", groups);
    }
}

@JsonDeserialize(using=CustomDeserializer.class)
public static class Group {
    String id;
    List<Integer> values;
    @Override
    public String toString() {
        return String.format("Group [id=%s, values=%s]", id, values);
    }
}

反序列化器，注意使用ObjectMapper.readTree而不是使用低级JsonParser API ......

public static class CustomDeserializer extends JsonDeserializer<Group> {

    @Override
    public Group deserialize(JsonParser jp, DeserializationContext ctxt)
            throws IOException, JsonProcessingException {
        Group group = new Group();
        ObjectNode objectNode = new ObjectMapper().readTree(jp);
        // assume only a single field...
        Entry<String, JsonNode> field = objectNode.fields().next();
        group.id = field.getKey();

        // there might be a nicer way to do this...
        group.values = new ArrayList<Integer>();
        for (JsonNode node : ((ArrayNode)field.getValue())) {
            group.values.add(node.asInt());
        }
        return group;
    }
}

测试

public static void main(String[] args) throws Exception {
    String json = "{\"groups\": [{\"g1\":[1,2,5,6,7]},{\"g2\": [2,3,48,79]}]}";
    JsonFactory f = new JsonFactory();
    JsonParser jp = f.createParser(json);
    ObjectMapper mapper = new ObjectMapper();

    System.out.println(mapper.readValue(jp, Container.class));
}

输出

Container [groups=[Group [id=g1, values=[1, 2, 5, 6, 7]], Group [id=g2, values=[2, 3, 48, 79]]]]

如何将动态JSON属性映射到固定的POJO字段

1 个答案: