Question

编辑：为了使我们更容易，我们有两个表来进行此查询。

1）Account_Cycle_Activity

2）Card_Account

我们将从1）表中分析的五个列是。

ACCOUNT_ID
ACTIVITY_TYPE_CDE
CYCLE_CTR
ACTIVITY_GROUP_CODE
CYCLE_ACTIVITY_COUNT

和从2）表中需要知道的列是

ACCOUNT_ID
CYCLE_CTR

逻辑是：

在ACCOUNT_CYCLE_ACTIVITY表中找到一行ACTIVITY_TYPE_CODE ='007'或'011'或'021'和ACTIVITY_GROUP_CODE ='R12'且CYCLE_ACTIVITY_AMOUNT大于$ 25且CYCLE_ACTIVITY_COUNT介于1到900之间 - 这是第一个条款我的询问。

对于我们刚刚找到的行，其CYCLE_CTR列应该等于CARD_ACCOUNT表CYCLE_CTR减去1的CYCLE_CTR列值。 - 这是第二个子句

现在这是查询的EXIST部分    如果您找到这样的行，并且表中也没有相同的ACCOUNT_ID具有相同的ACTIVITY_TYPE_CODE和相同的ACTIVITY_GROUP_CODE和CYCLE_ACTIVITY_COUNT = 1且CYCLE_CTR位于第一行的CYCLE_CTR -6到第一行的CYCLE_CTR - 1之间的任何位置，报告帐户。

我提出了以下查询

             SELECT *
             FROM ACCOUNT_CYCLE_ACTIVITY aca 
             inner join card_account ca on ca.account_id = aca.ACCOUNT_ID
             WHERE ACTIVITY_TYPE_CODE in('011', '021', '007') 
             and ACTIVITY_GROUP_CODE= 'R12'
             and (CYCLE_ACTIVITY_AMOUNT) > 25 
             and CYCLE_ACTIVITY_COUNT =1
             and aca.cycle_ctr = ca.cycle_ctr - 1
             and NOT EXISTS 
                        (SELECT aca2.ACCOUNT_ID
                         FROM ACCOUNT_CYCLE_ACTIVITY aca2 
                         where ca.account_id = aca2.ACCOUNT_ID
                         and aca2.ACTIVITY_TYPE_CODE=aca.activity_type_code 
                         and aca2.ACTIVITY_GROUP_CODE= aca.activity_group_code
                         and CYCLE_ACTIVITY_COUNT =1
                         and aca2.cycle_ctr between aca.cycle_ctr - 6 and aca.cycle_ctr - 1);

关于如何更有效地编写它以改善运行时间的任何想法？

Answer 1

尝试左（外）联接

SELECT aca.*, ca.* 
FROM card_account ca
inner join ACCOUNT_CYCLE_ACTIVITY aca  
        on aca.account_id = ca.ACCOUNT_ID
       and aca.ACTIVITY_TYPE_CODE in ('011', '021', '007') 
       and aca.ACTIVITY_GROUP_CODE = 'R12'           
       and aca.CYCLE_ACTIVITY_COUNT = 1 
       and aca.cycle_ctr = ca.cycle_ctr - 1 
       and aca.CYCLE_ACTIVITY_AMOUNT > 25 
 left join ACCOUNT_CYCLE_ACTIVITY aca2
        on aca2.account_id           = aca.ACCOUNT_ID
       and aca2.ACTIVITY_TYPE_CODE   = aca.activity_type_code 
       and aca2.ACTIVITY_GROUP_CODE  = aca.activity_group_code
       and aca2.CYCLE_ACTIVITY_COUNT = aca.CYCLE_ACTIVITY_COUNT
       and aca2.cycle_ctr      between aca.cycle_ctr - 6 and aca.cycle_ctr - 1           
where aca2.ACCOUNT_ID is null

此查询的最佳SQL

1 个答案: