Question

我有一个客户表和第二个反馈表。他们之间的Comman字段是CustomerId。我知道sql join查询，但我想在JSP中查询restful webservice。我写下这个代码，它抛出了内部服务器错误（500）。我希望它需要一个自定义类，因为结果我们返回一个List＆lt;＆gt ;.但我完全不知道。

@GET
        @Path("/all")
        @Produces({"application/json"})
        public List<Feedback> find() {
            return getEntityManager().createQuery("SELECT f.feedback,c.firstName FROM Feedback f INNERJOIN Customerdetail c on f.customerId=c.customerId")
                    .getResultList();
        }



    java.lang.IllegalArgumentException: An exception occurred while creating a query in EntityManager: 
    Exception Description: Syntax error parsing [SELECT f.feedback,c.firstName FROM Feedback f INNERJOIN Customerdetail c on f.customerId=c.customerId]. 
    [46, 47] The FROM clause has 'Feedback f' and 'INNERJOIN Customerdetail' that are not separated by a comma.
    [71, 72] The FROM clause has 'INNERJOIN Customerdetail' and 'c on' that are not separated by a comma.
    [76, 77] The FROM clause has 'c on' and 'f.customerId=' that are not separated by a comma.
    [89, 90] The FROM clause has 'f.customerId=' and 'c.customerId' that are not separated by a comma.
    [74, 76] The identification variable 'on' cannot be a reserved word.
    [89, 90] The identification variable '=' cannot be a reserved word.
    [102, 102] An identification variable must be provided for a range variable declaration.

    root cause

    Exception [EclipseLink-0] (Eclipse Persistence Services - 2.5.0.v20130507-3faac2b): org.eclipse.persistence.exceptions.JPQLException
    Exception Description: Syntax error parsing [SELECT f.feedback,c.firstName FROM Feedback f INNERJOIN Customerdetail c on f.customerId=c.customerId]. 
    [46, 47] The FROM clause has 'Feedback f' and 'INNERJOIN Customerdetail' that are not separated by a comma.
    [71, 72] The FROM clause has 'INNERJOIN Customerdetail' and 'c on' that are not separated by a comma.
    [76, 77] The FROM clause has 'c on' and 'f.customerId=' that are not separated by a comma.
    [89, 90] The FROM clause has 'f.customerId=' and 'c.customerId' that are not separated by a comma.
    [74, 76] The identification variable 'on' cannot be a reserved word.
    [89, 90] The identification variable '=' cannot be a reserved word.
    [102, 102] An identification variable must be provided for a range variable declaration.

Answer 1

请在此处查看如何使用JPQL查询或使用Native查询。如果您向我们展示您的架构并描述您想要选择的内容，那么它也会很有帮助。 JPQL或本机查询： JPQL Querying

Answer 2

您的查询中存在拼写错误：INNER JOIN NOT INNERJOIN。

如何在jsp restful webservice中进行连接查询？

2 个答案: