Question

如何构建$array以便将其传递给json_encode

$output = json_encode($array);

输出将是：

$output = [
  {apples:"33" ,oranges:"22"},
  {apples:"44" ,oranges:"11"},
  {apples:"55" ,oranges:"66"},
]

我需要使用任何选项来获得我需要的输出吗？或者这就是我如何构建我的PHP数组？

Answer 1

这应该适合你：

[] = array
{} = object
key:value = key：value

<?php

    $array = [
          (object)["apples" => "33", "oranges" => "22"],
          (object)["apples" => "44", "oranges" => "11"],
          (object)["apples" => "55", "oranges" => "66"],
        ];


    echo $output = json_encode($array);

?>

输出：

[
    {
        "apples": "33",
        "oranges": "22"
    },
    {
        "apples": "44",
        "oranges": "11"
    },
    {
        "apples": "55",
        "oranges": "66"
    }
]

Answer 2

您只需要将一组关联数组传递给json_encode

$array = array (
    array(
        'apples'=>'33',
        'oranges'=>'22'
    ),
    array(
        'apples'=>'44',
        'oranges'=>'11'
    ),
    array(
        'apples'=>'55',
        'oranges'=>'66'
    )
);

Answer 3

你可以在json_encode($var)中传递一组关联数组。

$array = array (
array(
    'johan'=>'male',
    'age'=>'22'
),
array(
    'lucy'=>'female',
    'age'=>'24'
),
array(
    'donald'=>'male',
    'age'=>'28'
)

）;

你如何使用json_encode操纵输出？

3 个答案: