Question

我已经在线查看，但我无法就我遇到的问题找到详细的答案。我有一个看起来像这样的对象：

 {
"00001": {
    "sid": "00001",
    "oid": "00001",
    "name": "operation 0001 service 1",
    "description": "test operation 000001",
    "returntype": "something",
    "parameters": {
        "00001": {
            "pid": "00001",
            "name": "parameter 00001 operation 0001 service 1",
            "description": "test parameter 000001",
            "type": "something"
        }
    }
},
"00002": {
    "sid": "00002",
    "oid": "00002",
    "name": "operation 0001 service 2",
    "description": "test operation 000001",
    "returntype": "something",
    "parameters": {}
},
"00003": {
    "sid": "00003",
    "oid": "00003",
    "name": "operation 0001 service 3",
    "description": "test operation 000001",
    "returntype": "something",
    "parameters": {}
},
"00004": {
    "sid": "00004",
    "oid": "00004",
    "name": "operation 0001 service 4",
    "description": "test operation 000001",
    "returntype": "something",
    "parameters": {}
},
"00005": {
    "sid": "00005",
    "oid": "00005",
    "name": "operation 0001 service 5",
    "description": "test operation 000001",
    "returntype": "something",
    "parameters": {}
},
"00006": {
    "sid": "00001",
    "oid": "00006",
    "name": "operation 0001 service 6",
    "description": "test operation 000001",
    "returntype": "something",
    "parameters": {}
}
}

我正在尝试遍历对象并能够返回具有特定sid的那些（即00001）我在javascript中知道obj中有一个for var，但我不确定如何按顺序实现它获得所需的输出。任何帮助或指导将不胜感激。

Answer 1

如果你知道这只是一级深度（“sid”匹配只能在对象的第一级找到，而你也没有搜索嵌套对象），那么它更直接：

function findMatches(data, prop, val) {
    var item, matches = [];
    for (var obj in data) {
        item = data[obj];
        if (item[prop] === val) {
            matches.push(item);
        }
    }
    return matches;
}

var result = findMatches(myData, "sid", "00001");

工作演示：http://jsfiddle.net/jfriend00/s5xg1khy/

Answer 2

递归是要走的路。见@ T.J。克劳德的回答 Loop through nested objects with jQuery

迭代对象并过滤给定属性javascript中的特定值

2 个答案: