Question

我正在使用play.api.libs.json._库。我有这种Scala类。我需要以Json格式读/写这个类。因为Timestamp没有隐式的读/写器。我必须提供自己的。不幸的是，我尝试了几种方式。你能告诉我它是怎么做的吗？提前致谢！

case class Event(id: Long, startTime: Option[java.sql.Timestamp] = None, endTime: Option[java.sql.Timestamp] = None)

我想按照Json格式POST / GET

{
  "id": 1,
  "startTime": "2011-10-02 18:48:05.123456",
  "endTime": "2011-10-02 20:48:05.123456"
}

Answer 1

只需在Json Reader或Json Format for Event class

之前添加

import play.api.libs.json.Json._
import play.api.libs.json._ 

def timestampToDateTime(t: Timestamp): DateTime = new DateTime(t.getTime)

def dateTimeToTimestamp(dt: DateTime): Timestamp = new Timestamp(dt.getMillis)

implicit val timestampFormat = new Format[Timestamp] {

    def writes(t: Timestamp): JsValue = toJson(timestampToDateTime(t))

    def reads(json: JsValue): JsResult[Timestamp] = fromJson[DateTime](json).map(dateTimeToTimestamp)

  }

Answer 2

我为个人项目编写的代码：

implicit object timestampFormat extends Format[Timestamp] {
  val format = new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ss.SS'Z'")
  def reads(json: JsValue) = {
    val str = json.as[String]
    JsSuccess(new Timestamp(format.parse(str).getTime))
  }
  def writes(ts: Timestamp) = JsString(format.format(ts))
}

不要忘记导入此内容：

import java.sql.Timestamp
import java.text.SimpleDateFormat
import play.api.Play.current
import play.api.libs.json._

它尊重Javascript日期标准。

来源：https://github.com/BinaryBrain/Gamers/blob/master/server/play/app/models/Package.scala

用于Timestamp的Scala playframework隐式读写器

2 个答案: