Question

我目前正在编写一个程序来检查汽车及其车牌的速度，我想重复执行这个x次的功能，我遇到的问题是该功能正在无休止地重复，并没有坚持我希望它循环的次数。以下是我到目前为止的情况：

    if correctMatch:
    pass
else:
    with open('Camera Output.txt', 'a') as f:
        print("DATA RECORDED TO: Camera Output.txt")
        exactTime2 = datetime.now()
        f.write("{} has a non-standard license plate and has been recorded at {}.".format(licensePlate,
                                                                                              exactTime2) + "\n")
        f.write("---------------------------------------------------------\n")
if speedCarMph > 60:
    with open('Camera Output.txt', 'a') as f:
        print("DATA RECORDED TO: Camera Output.txt")
        exactTime= datetime.now()
        f.write("{} was travelling at {}MPH, recorded at {} and has broken the law.".format(licensePlate,
                                                                                                speedCarMph, exactTime) + "\n")
        f.write("----------------------------------------------------------\n")
licensePlateCheck()
for x in range(N):
    repeatNum = 0
    while repeatNum < 10:
        repeatNum += 1
        licensePlateCheck()
    if repeatNum == 10:
        print("Completed generation")

我也尝试过使用一个帖子但是没有用。如果您需要更多代码，请询问。完整代码在这里（不包括不相关的函数和函数选择）：

import re
import threading
from queue import Queue
def licensePlateCheck():
   camInput1 = datetime.now()
   print(camInput1)
   print("Car is travelling...")
   time.sleep(0.1)
   print("Car has passed cam2")
   camInput2 = timedelta(seconds = random.uniform(5, 10))
   distance = 200
   duration = camInput2.total_seconds()
   print("Time Delta is equal to: {0}".format(duration))
   speedCarMs = distance/duration
   print("Car is travelling in m/s at: {0}".format(speedCarMs))
   speedCarMph = 2.237*speedCarMs
   print("Car is travelling in MPH at: {0}".format(speedCarMph))
   licenseCharNum = randint(2,9)
   licensePlate = ''.join(random.SystemRandom().choice(string.ascii_uppercase + string.digits) for _ in range(licenseCharNum))
   licensePlateLayout = re.compile('[A-Z][A-Z]\d\d[A-Z][A-Z][A-Z]')
   correctMatch = licensePlateLayout.match(licensePlate)
   if correctMatch:
      pass
   else:
      with open('Camera Output.txt', 'a') as f:
         print("DATA RECORDED TO: Camera Output.txt")
         exactTime2 = datetime.now()
         f.write("{} has a non-standard license plate and has been recorded at {}.".format(licensePlate,
                                                                               exactTime2) + "\n")
        f.write("----------------------------------------------------------\n")
   if speedCarMph > 60:
      with open('Camera Output.txt', 'a') as f:
         print("DATA RECORDED TO: Camera Output.txt")
         exactTime= datetime.now()
         f.write("{} was travelling at {}MPH, recorded at {} and has broken the law.".format(licensePlate,
                                                                                                speedCarMph, exactTime) + "\n")
        f.write("----------------------------------------------------------\n")
   licensePlateCheck()
   for x in range(N):
      repeatNum = 0
      while repeatNum < 10:
         repeatNum += 1
         licensePlateCheck()
      if repeatNum == 10:
         print("Completed generation")

Answer 1

在这种情况下，你有不必要的使用while循环：）

for x in range(N): // will iterate x times
    licensePlateCheck()

print("Completed generation")

使用嵌套的while循环，您的方法将执行：

x * 10次：

x - for loop
10 - while loop

For和While都是正确的，选择取决于你。

Python For循环无休止地重复

1 个答案: