我有一个拥有大量业务及其关系的数据库。我试图找到一种方法来获得B2销售给B1的所有商家也不卖。但只有在B1和B2销售给同一业务的B2上。
V =供应商，C =客户，两者都是企业，但从供应商/客户的角度考虑使这更容易解释。
V1 -sells to-＆gt; C1＆lt; - 卖给 - V2-销售 - ＆gt; C2
我正在寻找在特定V1起点不在C1中的所有C2。
我目前的表格：
mysql> DESCRIBE business;
+---------------+-------------------+------+-----+----------+----------------+
| Field | Type | Null | Key | Default | Extra |
+---------------+-------------------+------+-----+----------+----------------+
| business_id | int(11) | NO | PRI | NULL | auto_increment |
| email | varchar(255) | YES | | | |
| name | varchar(255) | NO | | NULL | |
| city | varchar(255) | YES | | | |
| state | varchar(255) | YES | MUL | | |
| cCount | int(10) unsigned | YES | MUL | 0 | |
| scCount | int(10) unsigned | YES | MUL | 0 | |
| vCount | int(10) unsigned | YES | MUL | 0 | |
| svCount | int(10) unsigned | YES | MUL | 0 | |
+---------------+-------------------+------+-----+----------+----------------+
mysql> DESCRIBE relation_sells_to;
+---------+----------+------+-----+---------+--------+
| Field | Type | Null | Key | Default | Extra |
+---------+----------+------+-----+---------+--------+
| start | int(11) | NO | MUL | NULL | |
| end | int(11) | NO | MUL | NULL | |
+---------+----------+------+-----+---------+--------+
mysql> DESCRIBE vcvc;
+---------+---------+------+-----+---------+-------+
| Field | Type | Null | Key | Default | Extra |
+---------+---------+------+-----+---------+-------+
| vendor | int(11) | NO | MUL | NULL | |
| client | int(11) | NO | | NULL | |
| vendor2 | int(11) | NO | | NULL | |
| client2 | int(11) | NO | | NULL | |
+---------+---------+------+-----+---------+-------+
我可以使用这两个查询来获取最新结果，但是我每次要更新它时都必须删除vcvc表，并且目前需要15分钟才能构建它。我也不需要在任何时候访问所有这些信息。我可能需要一次生成几千个这些列表，而不是完整的数据库。
CREATE TABLE IF NOT EXISTS vcvc (INDEX vendor (vendor), INDEX client2 (client2))
SELECT r.start AS vendor, r.end AS client, r2.start AS vendor2, r3.end AS client2
FROM relation_sells_to AS r
JOIN relation_sells_to as r2 ON r.end = r2.end
JOIN relation_sells_to AS r3 ON r2.start = r3.start
WHERE r.start != r2.start
AND r.end != r3.end;
SELECT DISTINCT(client2), cCount, scCount, vCount, svCount
FROM vcvc
JOIN business AS b ON client2=b.business_id
WHERE vendor = ####
AND client2 NOT IN (SELECT client FROM vcvc WHERE vendor = ####)
ORDER BY cCount DESC;
有没有办法在单个查询中执行此操作，因此每次需要获取此信息时，我都不必构建一个全新的表？我目前有500k的关系，当我建立这个表时，我最终有超过1亿行和大多数我不需要的行。理想情况下，我可以将电子邮件（首选）或business_id作为起始业务/供应商，然后只返回名称，城市，州，cCount，vCount的业务/客户列表，并按vCount顺序以DESC顺序进行订购。可能是LIMIT 20ish。速度不是一个巨大的问题我真的只是希望能够获得当前的结果，而不必构建一个大表，其中我需要20个100 +百万行。我最初尝试使用临时表，但因为我不能重新打开＃34;临时表就像我当前的查询需要一样。
感谢您的帮助。
使用样本数据和所需输出进行更新。 有些cCount和vCounts可能已关闭，我复制了实际数据然后对其进行了修改，但我不知道是否正确更新了所有数字，因为我添加了所需的连接以显示我需要的内容。
mysql> SELECT * FROM business;
+-------------+----------------+----------------------+----------------+------------+--------+---------+--------+---------+
| business_id | email | name | city | state | cCount | scCount | vCount | svCount |
+-------------+----------------+----------------------+----------------+------------+--------+---------+--------+---------+
| 1 | bob@bob.com | Bobs Construction | Virginia Beach | Virginia | 62 | 3 | 0 | 0 |
| 2 | sue@bob.com | Upholstery by Sue | Austin | Texas | 20 | 3 | 4 | 4 |
| 3 | jim@bob.com | Jim & Associates | Crowley | Texas | 5 | 3 | 0 | 0 |
| 4 | jon@bob.com | Jon Jon architects | Costa Mesa | California | 67 | 3 | 0 | 0 |
| 5 | joe@bob.com | Joes Pizza | Hamden | Conecticut | 7 | 1 | 0 | 0 |
| 6 | tim@bob.com | Tims WIndows | Miami | Florida | 10 | 2 | 0 | 0 |
| 7 | ron@bob.com | Rons Hot Rods | Costa Mesa | California | 8 | 4 | 0 | 0 |
+-------------+----------------+----------------------+----------------+------------+--------+---------+--------+---------+
mysql> SELECT start, end FROM relation_sells_to;
+-------+--------+
| start | end |
+-------+--------+
| 3 | 1 |
| 3 | 2 |
| 2 | 4 |
| 2 | 5 |
| 4 | 2 |
| 1 | 5 |
| 4 | 5 |
| 4 | 6 |
| 4 | 7 |
+-------+--------+
-- Run code to build vcvc table. Code is above.
mysql> SELECT * FROM vcvc WHERE vendor = 3;
+--------+--------+---------+---------+
| vendor | client | vendor2 | client2 |
+--------+--------+---------+---------+
| 3 | 1 | 2 | 4 |
| 3 | 1 | 2 | 5 |
| 3 | 1 | 4 | 2 |
| 3 | 2 | 1 | 5 |
| 3 | 2 | 4 | 5 |
| 3 | 2 | 4 | 6 |
| 3 | 2 | 4 | 7 |
+--------+--------+---------+---------+
Desired Output:
Select client_id, name, city, state, cCount, vCount FROM MAGIC WHERE email = jim@bob.com
+-----------+---------------------+----------------+------------+--------+---------+
| client_id | name | city | state | cCount | vCount |
+-----------+---------------------+----------------+------------+--------+---------+
| 4 | Jon Jon architects | Costa Mesa | California | 67 | 0 |
| 6 | Tims WIndows | Miami | Florida | 10 | 0 |
| 7 | Rons Hot Rods | Costa Mesa | California | 8 | 0 |
| 5 | Joes Pizza | Hamden | Conecticut | 7 | 0 |
+-----------+---------------------+----------------+------------+--------+---------+
-- Ordered by cCount, business_id 2 is NOT in this list because 3 sells to 2 so I don't care that 4 sells to 2.
更新2：
http://sqlfiddle.com/#!9/fdcec/2
这是一个小提琴。小提琴中的数据与上面的数据略有不同，因为它有2-3个连接来正确显示我想要的内容。