我正在使用Split字符串方法，我已经完成了将字符串拆分为固定长度的块，但问题是，它打破了这个词，我想保持完整的单词并在“SPACE”字符的基础上，拆分。
下面我也将功能与测试结果相关联。 请指导或指导我如何使用。
/*
Select dbo.SplitFixedLengthString('This is me , I am going to split this string in such a way that it will not break any word, rather it keeps word',16)
*/
CREATE FUNCTION [dbo].[SplitFixedLengthString]
(
@string NVARCHAR(MAX) ,
@stringlength INT
)
RETURNS NVARCHAR(MAX)
AS
BEGIN
DECLARE @tempStr NVARCHAR(MAX)
DECLARE @finalString NVARCHAR(MAX)
IF LEN(@string) > 0
AND @stringlength > 0
BEGIN
SELECT @tempStr = ''
DECLARE @i INT
SET @i = 1
WHILE @i <= LEN(@string)
BEGIN
SELECT @tempStr = @tempStr + SUBSTRING(@string, @i,@stringlength) + (CHAR(13) + CHAR(10))
SET @i = @i + @stringlength
END
END
RETURN @tempStr
END
测试结果：
This is me , I a
m going to split
this string in
such a way that
it will not brea
k any word, rath
er it keeps word
（1行（s）受影响） 正如我们所看到的那样，输出的第一行是将“am”这个单词分成4,5行。
请建议我解决。
以下是我的努力：
--DECLARE @x VARCHAR(32) = 'xyzxyzyyythgetdghydgsh j';
--SELECT LEN(@x) - CHARINDEX(' ', REVERSE(@x)) + 1;
DECLARE @string NVARCHAR(MAX)
SELECT @string = 'This is me , I am going to split this string in such a way that it will not break any word, rather it keeps word'
--SELECT @string = 'This is me,I am going to Trim off things in such a way that it will add newline having '
DECLARE @stringlength INT
SELECT @stringlength = 11
BEGIN
DECLARE @tempStr NVARCHAR(MAX)
DECLARE @finalString NVARCHAR(MAX) = ''
IF LEN(@string) > 0
AND @stringlength > 0
BEGIN
SELECT @tempStr = ''
DECLARE @start_index INT = 1
DECLARE @last_index INT = 0
DECLARE @lastindex INT = LEN(@string)-1
WHILE @start_index < @lastindex
BEGIN
SELECT @tempStr = SUBSTRING(@string, @start_index,@stringlength )
IF RIGHT(@tempStr,1) = ' '
BEGIN
SET @finalString = @finalString + @tempStr + (CHAR(13) + CHAR(10))
SET @start_index = @start_index + @stringlength
END
ELSE
BEGIN
--SELECT @last_index = LEN(@tempStr) - CHARINDEX(' ', REVERSE(@tempStr)) + 1;
SELECT @last_index = LEN(@tempStr) - CHARINDEX(' ',REVERSE(@tempStr))
IF @last_index = 0
BEGIN
SET @finalString = @finalString + LTRIM(SUBSTRING(@tempStr, 1,LEN(@tempStr)+1))+ (CHAR(13) + CHAR(10))
SET @start_index = @start_index + LEN(@tempStr)
END
ELSE
BEGIN
SET @finalString = @finalString + LTRIM(SUBSTRING(@tempStr, 1,@last_index +1))+ (CHAR(13) + CHAR(10))
SET @start_index = @start_index + @last_index
END
END
IF @start_index + @stringlength >= @lastindex
BEGIN
SET @finalString = @finalString + LTRIM(SUBSTRING(@string, @start_index,(@lastindex - @start_index)+1))+ (CHAR(13) + CHAR(10))
SET @start_index = @start_index + (@lastindex - @start_index)
END
END
END
SELECT @finalString
END
这是输出
----------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------
This is me
, I am
going to
split
this
string in
such a way
that it
will not
break any
word,
rather it
keeps wor
(1 row(s) affected)
答案 0 :(得分：1)
经过一番努力，我编写了这段代码。它的工作正常，虽然有点棘手。
ALTER FUNCTION [dbo].[SplitFixedLengthString]
(
@string NVARCHAR(MAX) ,
@stringlength INT
)
RETURNS NVARCHAR(MAX)
AS
BEGIN
DECLARE @tempStr NVARCHAR(MAX)
DECLARE @finalString NVARCHAR(MAX) = ''
IF LEN(@string) > 0
AND @stringlength > 0
BEGIN
SELECT @tempStr = ''
DECLARE @start_index INT = 1
DECLARE @last_index INT = 0
DECLARE @lastindex INT = LEN(@string)
DECLARE @NextChar VARCHAR(1) = ''
WHILE @start_index < @lastindex
BEGIN
SELECT @tempStr = SUBSTRING(@string, @start_index,@stringlength )
IF RIGHT(@tempStr,1) = ' '
BEGIN
SET @finalString = @finalString + @tempStr + (CHAR(13) + CHAR(10))
SET @start_index = @start_index + @stringlength
END
ELSE
BEGIN
SELECT @last_index = LEN(@tempStr) - CHARINDEX(' ',REVERSE(@tempStr))
SET @NextChar = SUBSTRING(@string, @start_index +LEN(@tempStr),1)
IF @last_index = 0 AND @NextChar = ' '
BEGIN
SET @finalString = @finalString + LTRIM(SUBSTRING(@tempStr, 1,LEN(@tempStr)-1))+(CHAR(13) )
SET @start_index = @start_index + LEN(@tempStr)
END
IF @last_index = 0 AND @NextChar <> ' '
BEGIN
SET @finalString = @finalString + LTRIM(SUBSTRING(@tempStr, 1,LEN(@tempStr)-1))+ '_'+ (CHAR(13) )
SET @start_index = @start_index + LEN(@tempStr) -1
END
ELSE IF (@last_index) = LEN(@tempStr)
BEGIN
SET @finalString = @finalString + LTRIM(SUBSTRING(@tempStr, 1,LEN(@tempStr)-1))+ '_'+ (CHAR(13) )
SET @start_index = @start_index + LEN(@tempStr) -1
END
ELSE IF @last_index <> 0 AND @NextChar = ' '
BEGIN
SET @finalString = @finalString + LTRIM(SUBSTRING(@tempStr, 1,LEN(@tempStr)))+ (CHAR(13) )
SET @start_index = @start_index + LEN(@tempStr)
END
ELSE IF (LEN(@tempStr) - @last_index) = 2 AND @NextChar <> ' '
BEGIN
SET @finalString = @finalString + LTRIM(SUBSTRING(@tempStr, 1,LEN(@tempStr)-1))+ (CHAR(13) )
SET @start_index = @start_index + LEN(@tempStr) -1
END
ELSE IF (@last_index) <> 0 AND @NextChar <> ' '
BEGIN
SET @finalString = @finalString + LTRIM(SUBSTRING(@tempStr, 1,LEN(@tempStr)-1))+ '_'+ (CHAR(13) )
SET @start_index = @start_index + LEN(@tempStr) -1
END
ELSE
BEGIN
SET @finalString = @finalString + LTRIM(SUBSTRING(@tempStr, 1,@last_index ))+ (CHAR(13) )
SET @start_index = @start_index + @last_index
END
END
IF @start_index + @stringlength >= @lastindex
BEGIN
SET @finalString = @finalString + LTRIM(SUBSTRING(@string, @start_index,(@lastindex - @start_index)+1))+ (CHAR(13) )
SET @start_index = @start_index + (@lastindex - @start_index)
END
END
END
RETURN @finalString
END