如何在Parse iOS中从同一个键获取数据?

时间:2015-03-02 05:08:32

标签: ios parse-platform

我是Parse.com的新手我试着用相同的键从Parse表中获取数据但是值不同如

-(void)getdata
{
NSMutableArray *allObjects = [NSMutableArray array];
NSUInteger limit = 1000;
__block NSUInteger skip = 0;
PFQuery *query = [PFQuery queryWithClassName:@"MapInfo"];
PFQuery *query = [PFQuery queryWithClassName:@"MapInfo"];
[query whereKey:@"Type" containedIn:@[@"Temopary", @"Business"]];
[query setLimit: limit];
[query setSkip: skip];
[query findObjectsInBackgroundWithBlock:^(NSArray *objects, NSError *error)      {
    if (!error) {
        [allObjects addObjectsFromArray:objects];
        if (objects.count == limit) {

            skip += limit;
            [query setSkip: skip];
            [query findObjectsInBackgroundWithBlock:^(NSArray *objects, NSError *error) {
                [allObjects addObjectsFromArray:objects];
                self.lqpinname=[allObjects valueForKey:@"GPIN"];
                NSLog(@"Qpin name COunt %@",self.lqpinname);
                self.locationArray=[allObjects valueForKey:@"Location"];
                self.llatitude=[self.locationArray valueForKey:@"lat"];
                self.llongitude=[self.locationArray valueForKey:@"lng"];
                self.laddress=[allObjects valueForKey:@"Address"];
                self.lusernameArray=[allObjects valueForKey:@"AddedBy"];
                hudView.hidden=TRUE;
            }];
        }
    }
    else
    {
        NSLog(@"Error: %@ %@", error, [error userInfo]);
    }
}];
}   

但是这里返回Null值我想从表中获取数据Type=Business & Temporary列请给我解决方案。

感谢。

1 个答案:

答案 0 :(得分:1)

您应该可以使用whereKey:containedIn:来执行此操作。

PFQuery *query = [PFQuery queryWithClassName:@"MapInfo"];
[query whereKey:@"Type" containedIn:@[@"Temopary", @"Business"]];

你也有临时错字(除非Temporay是东西) - 不确定这是否是故意的。