PHP SQL循环输出为0行

Question

我正在尝试创建一个PHP循环来向玩家展示他们参与的锦标赛。我在phpMyAdmin上尝试了这个功能，我得到了我想要的结果。但是当我尝试在PHP上运行这个简单的脚本时，它输出为0行。

的index.php

chdir("../"); // path to MyBB
define("IN_MYBB", 1);
require("./global.php");

if($mybb->user['uid']) {
    $sql = "SELECT * FROM players, tourneys WHERE players.forumname = 1 AND players.tid = tourneys.id";
    $result = mysqli_query($conn, $sql);
    // output data of each row
    if (mysqli_num_rows($result) > 0) {
        // output data of each ro
        while($row = mysqli_fetch_assoc($result)) {
            $name = $row['name'];
            $date = $row['date'];
            $time = $row['time'];
            echo $name;
            echo $date;
            echo $time;
        }
    } else {
        echo "0 rows";
    }
}

Answer 1

问题不在＆＃34; if（$ mybb-＆gt; user [＆＃39; uid＆＃39;]）{＆＃34;正如@Dagon所建议的那样。尝试保留缩进的代码以避免这种混淆。运行下面的代码并发布DB错误输出。

试试这个：

<?php
chdir("../"); // path to MyBB
define("IN_MYBB", 1);
require("./global.php");

if ($mybb->user['uid']) {

    $player_forumname = '1';

    // Return only the necessary fields
    $sql = "SELECT tourneys.name, tourneys.date, tourneys.time
            FROM tourneys
            INNER JOIN players ON players.tid = tourneys.id
            WHERE players.forumname = {$player_forumname}";

    $result = mysqli_query($conn, $sql);

    // If the query fails display the error
    if ($result === FALSE) {
        die('MySQLi Error: ' . mysqli_error($conn));
    }

    if (mysqli_num_rows($result) == 0) {
        die('0 rows');
    }

    // Returns only the associative array
    while ($row = mysqli_fetch_array($result, MYSQLI_ASSOC)) {
        $name = $row['name'];
        $date = $row['date'];
        $time = $row['time'];

        echo 'Name:',$row['name'],'Date:',$row['date'],'Time:',$row['time'];
    }
}