我试图阅读一堆行并显示它们而没有通常的" ARRAY =>"废话,但我得到的只是这个错误
注意:未定义的变量:第0行的C:\ xampp \ htdocs \ sql.php中的数据
这是我的代码:
<?php virtual('/Connections/TDBS_local.php');
$query = "SELECT sub_category FROM sub_category WHERE main_category_id = 2 ";
$result = mysqli_query($TDBS_local, $query);
if ($result = mysqli_query($TDBS_local, $query)) {
/* fetch associative array */
if($row = mysqli_fetch_assoc($result)) {
$data = unserialize($row['sub_category']);
}
/* free result set */
mysqli_free_result($result);
}
print "<pre>";
print_r($data);
print "</pre>";
?>
我哪里错了?
答案 0 :(得分:1)
以下是如何使用pdo,mysqli和mysql
的mysqli
$con=mysqli_connect("localhost","username","password","dbname");
$sql="SELECT sub_category FROM sub_category WHERE main_category_id = 2";
$result=mysqli_query($con,$sql);
$new_array = array();
while ($row = mysqli_fetch_array($result,MYSQLI_ASSOC)){
$new_array[] = $row;
}
print_r($new_array);
mysqli_free_result($result);
mysqli_close($con);
MYSQL
mysql_connect("localhost","username","password");
mysql_select_db("dbname");
$result = mysql_query("SELECT sub_category FROM sub_category WHERE main_category_id = 2");
$new_array = array();
while ($row = mysql_fetch_array($result)) {
$new_array[] = $row;
}
print_r($new_array);
PDO
$pdo = new PDO('mysql:host=localhost;dbname=dbname', 'username', 'password');
$statement = $pdo->query("SELECT sub_category FROM sub_category WHERE main_category_id = 2");
$new_array = array();
while ($row = $statement->fetch(PDO::FETCH_ASSOC)) {
$new_array[] = $row;
}
print_r($new_array);
答案 1 :(得分:0)
我认为你必须使用require或include而不是virtual:
<?php
require('Connections/TDBS_local.php');
$data = '';
$query = "SELECT sub_category FROM sub_category WHERE main_category_id = 2 ";
$result = mysqli_query($TDBS_local, $query);
if ($result = mysqli_query($TDBS_local, $query)) {
/* fetch associative array */
if($row = mysqli_fetch_assoc($result)) {
$data = unserialize($row['sub_category']);
}
/* free result set */
mysqli_free_result($result);
}
print "<pre>";
print_r($data);
print "</pre>";
?>