Question

我有这个功能来检查某些单词是否出现在特定行中，然后用给定的字符括起来。

上面的代码就像一个魅力，但是因为字符串数组中的单词＆＃34;单词＆＃34;总是低的情况下，单词也会是小写的。我该如何解决这个问题？

输入：

BufferedReader in = "Hello, my name is John:";
char c = '*';
String [] words = {"hello","john"};

所需的输出：

BufferedWriter out = "*Hello*, my name is *John*:";

实际输出：

BufferedWriter out = "*hello*, my name is *john*";

代码：

public void replaceString(BufferedReader in, BufferedWriter out, char c, String[] words){

String line_in = in.readLine();

    while (line_in != null) {
        for (int j = 0; j < words.length; j++) {

            line_in = line_in.replaceAll("(?i)" + words[j], bold + words[j]
                    + bold);

        }

        out.write(line_in);
        out.newLine();
        line_in = in.readLine();

    }
}

Answer 1

使用

line_in.replaceAll("(?i)(" + words[j] + ")", bold + "$1" + bold);
//                      \________________/           \/
//                         capture word          reference it

替换字符串Java

1 个答案: