Question

如何让产品拥有所有请求的属性

SELECT * FROM `oc_product_attribute` WHERE (`attribute_id`=15 AND `text`="2500") OR (`attribute_id`=18 AND `text`="24")

此请求，返回以下结果：

|product_id | attribute_id | language_id | text
+-----------+--------------+-------------+-----
|1          | 15           | 1           | 2500
|2          | 15           | 1           | 2500
|3          | 15           | 1           | 2500
|4          | 15           | 1           | 2500
|3          | 18           | 1           | 24  
|4          | 18           | 1           | 24

但我只需要产品3和4，因为它们有15 = 2500和18 = 24。我是怎么做到的？

Answer 1

如果你想匹配多个条件并返回匹配所有条件的值，这是一种方法

select p1.* from oc_product_attribute p1
where 
p1.`attribute_id`=15 AND p1.`text`='2500'
and exists
(
  select 1 from oc_product_attribute p2
  where
  p2.attribute_id = 18 
  and p2.text = 24
  and p1.product_id = p2.product_id
)
union all
select p1.* from oc_product_attribute p1
where 
p1.`attribute_id`=18 AND p1.`text`='24'
and exists
(
  select 1 from oc_product_attribute p2
  where
  p2.attribute_id = 15 
  and p2.text = 2500
  and p1.product_id = p2.product_id
)
;

Answer 2

SELECT product_id 
  FROM oc_product_attribute
 WHERE (attribute_id,text) IN ((15,'2500'),(18,'24')) 
 GROUP 
    BY product_id 
HAVING COUNT(DISTINCT attribute_id,text) = 2;

我有一种感觉，这种速记否定了索引的使用，但希望你能得到这个想法。

MySQL产品按多个属性过滤

2 个答案: