我有表loadhistory(计划到"每个日期只选择最高值"按日期分组和按日期DESC排序)
| user_id | customer_id | date | bal |
1 1 2015-02-27 500
2 1 2015-02-27 650
3 1 2015-02-28 450
4 1 2015-02-28 620
和表事务记录(并计划使用SUM(bal)组和按日期DESC排序每个日期的值)
| user_id | customer_id | date | bal |
1 1 2015-02-27 50
2 1 2015-02-27 20
3 1 2015-02-28 10
但我想加入两个看起来像这样的表:
| date | balance | amount paid |
2015-02-28 620 10
2015-02-27 650 70
我不善于加入表格。到目前为止,这是我的代码,无法正常工作
$q = "SELECT a.customer_id, SUM(a.bal), a.date, MAX(b.bal) GROUP BY date
FROM transactionrecord as a
LEFT JOIN loadhistory as b ON b.customer_id = a.customer_id
WHERE customer_id = {$_COOKIE['id']} GROUP BY date
ORDER BY date DESC";
$r = @mysqli_query ($dbc, $q );
echo '<table align="center" cellspacing="0" cellpadding="5" width="45%">
<tr>
<td align="center"><b>Date</b></td>
<td align="center"><b>Balance</b></td>
<td align="center"><b>>Amount Paid></b></td>
</tr>';
while ($row = mysqli_fetch_array($r, MYSQLI_ASSOC)) {
echo '
<td align="center">' . $row['date'] . '</td>
<td align="center">' . $row['MAX(b.bal)'] . '</td>
<td align="center">' . $row['SUM(a.bal)'] . '</td>
';
在我的查询中要更改什么来加入包含SUM()和MAX()的2个表?我使用的是$ row [&#39; &#39;]在echo中对吗?
非常感谢。
答案 0 :(得分:0)
您的SQL语句应该如下所示,以达到您想要的结果:
SELECT a.customer_id, a.date, MAX(COALESCE(b.bal, 0)) AS bal, a.paid
FROM (
SELECT customer_id, date, SUM(bal) AS paid
FROM transactionrecord
GROUP BY customer_id, date
) AS a LEFT JOIN loadhistory AS b
ON a.customer_id = b.customer_id AND a.date = b.date
WHERE a.customer_id = 1
GROUP BY a.customer_id, a.date, a.paid
ORDER BY a.date DESC
在您的php中,您无法使用MAX(b.bal)
或SUM(a.bal)
来引用结果列;相反,您必须按照我上面所做的那样为列添加别名。因此,您可以将MAX(b.bal)
称为bal
,您可以将SUM(a.bal)
称为paid
。
你们大多数都拥有SQL权利,我只是
GROUP BY
表达式,SUM
和MAX
)列添加了别名,loadhistory
表中多行的乘法结果date
和customer_id
列的所有提及进行了限定,因为这些列都显示在两个表中,COALESCE
上添加了bal
,以防左联接导致没有匹配的loadhistory
记录,date
上添加了加入条件,因为记录必须具有与您的要求相当的customer_id
和date
,并且customer_id
添加到GROUP BY
子句中,因为SELECT
子句中的任何非聚合字段都应位于GROUP BY
子句中,以获得可预测的结果。如果您想在表格user_id
而不是date
中选择loadhistory
每MAX(bal)
个最高的值,则需要执行以下操作:
SELECT b.user_id, a.customer_id, a.date,
COALESCE(b.bal, 0) AS bal, SUM(a.bal) AS paid
FROM transactionrecord AS a LEFT JOIN (
SELECT h1.user_id, h1.customer_id, h1.date, h1.bal
FROM loadhistory h1 INNER JOIN (
SELECT MAX(user_id) AS user_id, customer_id, date
FROM loadhistory GROUP BY customer_id, date
) AS h2 ON h1.user_id = h2.user_id
AND h1.customer_id = h2.customer_id
AND h1.date = h2.date
) AS b ON a.customer_id = b.customer_id AND a.date = b.date
WHERE a.customer_id = 1
GROUP BY b.user_id, a.customer_id, a.date, b.bal
ORDER BY a.date DESC