Question

如图所示，我编写了此代码，并为CASH和TOTAL分配了值。我无法理解的是为什么我得到..... ＆＃34; Traceback（最近一次调用最后一次）：文件＆＃34; C：\ Python27 \ Checkout Counter2.py＆＃34;，第29行，in 变化=现金 - 总计 TypeError：不支持的操作数类型 - ：＆＃39; str＆＃39;和＆＃39; str＆＃39;＆＃34;

我已经尝试了多种方法来完成这项工作，但我发现它与找到总数之间没有任何区别。

 print "Welcome to the checkout counter!  How many items are you purchasing today?"
    #NOI is number of items
    NOI = int(raw_input())
    productlist = []
    pricelist=[]
    for counter in range(NOI):
        print"Please enter the name of product", counter+1 
        productlist.append(raw_input())    

    print"And how much does", productlist[len(productlist)-1], "cost?"
    pricelist.append(float(raw_input()))
    if pricelist[len(pricelist)-1] < 0:
        pricelist.pop()
        productlist.pop()
        len(productlist)-1
        len(pricelist)-1

print "Your order was:"
subtotal=0.00
for counter in range(NOI):
    print productlist[counter],
    print "$%0.2f" % pricelist[counter]
    subtotal += pricelist[counter]
    total = "$%0.2f" % float(subtotal + (subtotal * .09))
print "Your subtotal comes to", "$" + str(subtotal) + ".", " With 9% sales tax, your total is " + str(total) + "."
print "Please enter cash amount:"
cash = raw_input()
while True:
    change = cash - total
    if cash < total:
        print "You need to give more money to buy these items. Please try again."
    else:
        print "I owe you back", "$" + float(change)

Answer 1

“raw_input”将始终返回一个字符串（即使您输入3或3.5）

因此你必须：

cash = float(cash)
total = float(total)

编辑：此外，当你这样做：

total = "$%0.2f" % float(subtotal + (subtotal * .09))

total也将是一个字符串，这就是为什么你还必须将它转换为float。

希望它有所帮助。

尝试使用附加值的两个字符串并减去它们

1 个答案: