在C#/ XAML中旋转BitmapImage

时间:2015-02-28 20:55:05

标签: c# wpf xaml

我在列表中有2个BitmapImages:

    BitmapImage img1 = new BitmapImage((new Uri("Images/image1.jpg", UriKind.Relative)));
    BitmapImage img1 = new BitmapImage((new Uri("Images/image2.jpg", UriKind.Relative)));

    List<BitmapImage> images = new List<BitmapImage>();

    images.Add(img1);
    images.Add(img2);

如何通过按下按钮来旋转两个位图图像?

我已经尝试过MSDN的解决方案(如下所示),但我得到“没有'源'的定义”。

private void TurnLeft_Click(object sender, RoutedEventArgs e)
{
    //Create source
    BitmapImage bi = new BitmapImage();

    //BitmapImage properties must be in a BeginInit/EndInit block
    bi.BeginInit();
    bi.UriSource = new Uri("Images/image1.jpg", UriKind.Relative);

    //Set image rotation
    bi.Rotation = Rotation.Rotate270;
    bi.EndInit();

    //set BitmapImage "img2" from List<BitmapImage> from source
    img2.Source = bi;
}   

2 个答案:

答案 0 :(得分:2)

查看以下代码段。

<强> XAML:

<Grid>
    <Grid.RowDefinitions>
        <RowDefinition Height="*"/>
        <RowDefinition Height="Auto"/>
    </Grid.RowDefinitions>

    <Image x:Name="Image1" Stretch="Uniform" >
        <Image.Source>
            <BitmapImage UriSource="Images/logo.png"/>
        </Image.Source>
    </Image>

    <Button x:Name="TurnLeftButton" Content="TurnLeft"
            Click="TurnLeftButton_Click"
            Grid.Row="1"/>
</Grid>

代码背后:

private void TurnLeftButton_Click(object sender, RoutedEventArgs e)
{
    var biOriginal = (BitmapImage) Image1.Source;

    var biRotated = new BitmapImage();
    biRotated.BeginInit();
    biRotated.UriSource = biOriginal.UriSource;
    biRotated.Rotation = Rotation.Rotate270;
    biRotated.EndInit();

    Image1.Source = biRotated;
}

答案 1 :(得分:0)

dbvega回答了我的问题。但是,有一个演员例外,我想我会为使用我的问题来解决你的错误的任何人解决它。

dbvega示例的正确C#代码应如下所示:

private void TurnLeftButton_Click(object sender, RoutedEventArgs e)
{
    var biRotated = new BitmapImage();
    biRotated.BeginInit();
    biRotated.UriSource = new Uri("Images/logo.png", UriKind.Relative);
    biRotated.Rotation = Rotation.Rotate270;
    biRotated.EndInit();

    Image1.Source = biRotated;
}

虽然骗了dbvega - 问题解决了!