所以我面临这个问题,我需要解析XML文件以弹出域对象。听起来很简单,但是,XML文件中的元素可以具有未知的子容量,因此域对象可以具有到该类的另一个对象的实例变量,该对象可以具有到同一类的实例变量的变量等等。举个例子,这是XML文件提供的示例:
<categories>
<category id="1">
<name>XML</name>
<category id="2">
<name>XPath</name>
</category>
<category id="3">
<name>XML Schema</name>
</category>
<category id="4">
<name>XSLT</name>
</category>
<category id="5">
<name>XSL-FO</name>
</category>
<category id="6">
<name>XQuery</name>
</category>
</category>
<category id="7">
<name>Java</name>
<category id="100">
<name>SDK</name>
<category id="8">
<name>Collections</name>
</category>
<category id="9">
<name>NIO</name>
</category>
<category id="10">
<name>Concurrency</name>
</category>
</category>
<category id="1000">
<name>EE</name>
<category id="11">
<name>EJB</name>
</category>
<category id="12">
<name>Web</name>
</category>
<category id="13">
<name>Webservices</name>
</category>
</category>
<category id="0">
<name>Examen boeken</name>
</category>
</category>
</categories>
我已经使用DOM解析器完成了这项工作但是对于我的研究,我需要使用SAX解析器来完成此操作。我陷入困境,我需要告诉哪个元素哪个元素作为子元素,哪个元素哪个元素作为父元素。
截至目前,我设法在包含其ID和名称的地图中获取所有类别条目。
代码如下所示:
public static void main(String[] args) throws SAXException, IOException,
ParserConfigurationException {
Bookshelf mijnBookshelf = new Bookshelf("boekenfestijn");
Map<Integer, Category> categories = new HashMap<Integer, Category>();
// TODO inlezen
try {
SAXParserFactory factory = SAXParserFactory.newInstance();
SAXParser saxParser = factory.newSAXParser();
DefaultHandler handler = new DefaultHandler() {
String reading = null;
boolean inCategory = false;
boolean inName = false;
int categoryId;
Category currentCategory;
public void startElement(String uri, String localName,
String qName, Attributes attributes)
throws SAXException {
if(qName.equalsIgnoreCase("CATEGORY") && attributes.getValue("id") != null){
inCategory = true;
categoryId = Integer.parseInt(attributes.getValue("id"));
System.out.println("START HANDLING ID -> " + attributes.getValue("id"));
}
if(qName.equalsIgnoreCase("NAME")){
inName = true;
}
}
public void endElement(String uri, String localName,
String qName) throws SAXException {
if(inCategory){
inCategory = false;
System.out.println("CATEGORY ID : " + categoryId + " NAME : " + reading);
currentCategory = new Category(categoryId, reading);
currentCategory.setBookshelf(mijnBookshelf);
categories.put(categoryId, currentCategory);
System.out.println("END HANDLING");
}
if(inName){
inName = false;
}
}
public void characters(char ch[], int start, int length)
throws SAXException {
reading = new String(ch, start, length);
}
};
saxParser.parse("bookshelf.xml", handler);
} catch (Exception e) {
e.printStackTrace();
}
for (Integer i : categories.keySet()) {
System.out.println("ID: " + categories.get(i).getId() + "->"
+ categories.get(i).getName());
}
对于“类别”类
public class Category {
private Integer id;
private String name;
private Category parent;
private List<Category> children = new ArrayList<Category>();
private Bookshelf bookshelf;
public Category(){
}
public Category(Integer id, String name) {
super();
this.id = id;
this.name = name;
}
public Integer getId() {
return id;
}
public void setId(Integer id) {
this.id = id;
}
public String getName() {
return name;
}
public void setName(String name) {
this.name = name;
}
public Category getParent() {
return parent;
}
public void setParent(Category parent){
this.parent = parent;
}
public List<Category> getChildren() {
return children;
}
public String toString() {
String s = bookshelf.getName() + "/";
if (parent != null) {
s = parent.toString();
}
s += name + "/";
return s;
}
public Bookshelf getBookshelf() {
return bookshelf;
}
public void setBookshelf(Bookshelf bookshelf) {
this.bookshelf = bookshelf;
}
这就是我陷入困境的地步?我怎么能继续定义父子关系?我怎么知道我的处理程序中的哪个元素具有哪个元素作为children / parent?
非常感谢任何帮助!
TLDR:在使用sax解析器填充域对象时,如何定义父/子关系?
答案 0 :(得分:2)
在SAX中,您无法直接知道哪个元素是另一个元素的父元素。处理此信息的常用方法是管理LIFO堆栈(例如java.util.Stack
)。您按startElement()
方法上的元素并将其弹出endElement()
。
不幸的是,由于startElement()
,您无法预测子元素,直到您“遇到”它们。