Question

最后我想用char乘以int，这是不可能的。如何得到像整数的x值？

{
char a[50];
int y;
    printf("Vyvedete imeto si i razberete koe e shtastlivoto vi chislo\n");
    cin >> a;
int x = printf(a) * 5;
    printf(" Your lucky number is %d\n", x);
    printf("But wait! There is more!\n Type another number!\n");
    cin >> y;
    printf(y*x);
return 0;

}

Answer 1

你试过这个：？

#include<stdio.h>
int main(void)
{
    char c='d';
    printf("the character before multiplication is %c and ascii representation is %d",c,c);
    int x=c*5;
    printf("the character after multiplication is %c and ascii representation is %d",x,x);
}

Answer 2

如何在C中将char值转换为int？

char 是整数。

#include <stdio.h>

...

char c = 'A';
printf("%d\n", c);

int i = c;
printf("%d\n", i);

i = 'B';
printf("%d\n", i);

c = i; /* For this you might get warned about loosing 
          significant digits during conversion as 
          char is 8 bit wide and int is wider. */
printf("%d\n", c);

打印

Answer 3

将您的代码更改为：

char a[50]=""; //initialize a
printf("Vyvedete imeto si i razberete koe e shtastlivoto vi chislo\n");
cin >> a; //better to use fgets/scanf
int x = strlen(a) * 5; //use strlen from string.h to get the length of a
printf(" Your lucky number is %d\n", x);

请注意，将C样式代码与C ++混合是一种不好的做法。使用cout和cin或printf和scanf。另请注意，如果要使用string.h函数，则需要包含cstdlib（strlen for C ++）。如果您使用的是C ++，则建议使用string数据类型。

如何将char值转换为int？

3 个答案: