Question

代码如下：在行旁边设置断点（断点1，断点2）。

＆＃13;

if (!TestSolution)
{
    var TestSolution= {};
}

TestSolution.Utils = TestSolution.Utils || {};

var dummy_ = (function ()
{
    // Sometimes step into the line just pop out. 
    // The following lines will not run. 
    **var self = this;**   // Break point 1. 

    // Subscribe to event optionally unsubscribing first.
    **this.Subscribe = function(source, eventName, handler, unsubscribe)** // Break point 2.
    {
        // By default - always unsubscribe first - there is hardly a reason to have
        // multiple subscriptions for the same combination of controls and events.
        if (!(unsubscribe === false)) $(source).off(eventName, handler);
        $(source).on(eventName, handler);
    }
}).call(TestSolution.Utils);

＆＃13;

问题是，有时候它会进入突破点1，而当按F11时，它并没有进入突破点2.我觉得＆＃34; var self = this;＆＃34;没有运行。它只是弹出功能。

编辑：这是在Chrome（版本41.0.2243.0（64位））中调试的。

Answer 1

此代码块非常奇怪，可能会导致竞争问题：

if (!TestSolution)
{
    var TestSolution= {};
}

我会把它改成

var TestSolution = TestSolution || {};

有时候Javascript代码在步入（F11）时不会执行？

1 个答案: