Question

在我的子查询中，我在Select stmt中有这一行来执行DATEDIFF：

DATEDIFF(day,[Invoice_Date], '2015-02-27 00:00:00.000') AS Days_AGED,

在我使用该INT或Number返回的主要查询中，我在我的select stmt中有以下代码进行测试：

(Days_AGED + 5) AS TEST_AGE, --This worked and gave me the correct number when 5 was added to the variable Days_AGED
    CASE
      WHEN (CAST(Days_AGED AS NUMERIC(10,0)) >= CAST(30 AS NUMERIC(10,0))) THEN CAST(Days_AGED AS VARCHAR(5)) + ' 0-30 Days' -- This worked when the number was 30 or a large number
      WHEN (Days_AGED >= 31 AND Days_AGED <= 60) THEN '31-60 Days'
      WHEN (Days_AGED >= 61 AND Days_AGED <= 90) THEN '61-90 Days'
      WHEN (Days_AGED >= 91 AND Days_AGED <= 120) THEN '91-120 Days'
      WHEN (Days_AGED >= 121 AND Days_AGED <= 150) THEN '121-150 Days'
      ELSE '151+ Days'
    END AS AGED_GRP

- 似乎数字在15到29之间，它将返回＆＃34; 151+天＆＃34;，这和＆＃34; 0-30＆＃34;似乎是唯一的回归结果。

如果我能够在第一次WHEN中为该INT值添加5，为什么我无法正确评估它？

我只是希望它成为我的CASE stmt评估的数字，这样我才能得到正确的结果。在此先感谢您的帮助。

Answer 1

您可以简化代码：

   CASE
      WHEN Days_AGED IS NULL THEN  NULL -- What should happen when Days_AGED contains NULLs ?
      WHEN Days_AGED <= 30  THEN '0-30 Days'
      WHEN Days_AGED <= 60  THEN '31-60 Days'
      WHEN Days_AGED <= 90  THEN '61-90 Days'
      WHEN Days_AGED <= 120 THEN '91-120 Days'
      WHEN Days_AGED <= 150 THEN '121-150 Days'
      ELSE '151+ Days'
    END AS AGED_GRP

或

CASE 
    WHEN Days_AGED IS NULL THEN  NULL 
    WHEN Days_AGED <= 150 THEN
        CONVERT(VARCHAR(11), ISNULL(NULLIF(((Days_AGED - 1) / 30) * 30, 0) + 1, 0)) + '-' + 
        CONVERT(VARCHAR(11), ((Days_AGED - 1) / 30 + 1) * 30) + ' Days'
    ELSE '151+ Days'
END

SQL Server比较来自DATEDIFF的INT不能像我预期的那样工作

1 个答案: