我有一个简单的问题。我想计算训练心率。我有一些价值观。 RHR意味着静息心率。 INTEN意味着fitnes水平,我为低,中,高健身水平给出值0.55,0.65,0.8我写了代码
Gender=input('Please input your gender: ');
Age=input('Please input your age: ');
RHR=input('Please enter your resting heart rate: ');
INTEN=input('Please enter your fitness level(low,medium or high): ');
male=Male;
female=Female;
low=0.55;
medium=0.65;
high=0.8;
if INTEN==0.55
INTENT=0.55;
elseif INTENT==medium
INTENT=0.65;
else
INTENT=0.8;
end
if Gender==Male
THR=((220-Age)-RHR)*INTEN+RHR;
elseif Gender==Female
THR=((206-0.88*Age)-RHR)*INTEN+RHR;
end
disp('The recommended training heart rate is ',num2str(THR))
但它给出了错误原因?
答案 0 :(得分:3)
您的代码中存在一些错误。值得注意的是,您使用保留的操作来将数字与字符串进行比较,这是不可能的。此外,变量Gender
应该是一个字符串,但是被操作为一个数字,这是令人困惑的。请务必查看用于将字符串进行比较的函数strcmp。然后,您可以使用if/elseif
块。
我建议使用prompt
来查询用户的信息。这样一切都在同一时间显示,在我看来更容易使用。
以下是带注释的代码。如果有什么不清楚请告诉我。
clc
clear
%// Set up dialog promt.
prompt = {'Enter your gender (male/female)','Enter your age:','Enter your resting heart rate: ','Enter your fitness level(low,medium or high): '};
dlg_title = 'Input';
num_lines = 1;
%// Default answers
def = {'male','30','120','medium'};
%// The answers are stored in the cell array called "answer". Its a 4x1
%// cell array containing ONLY STRINGS.
answer = inputdlg(prompt,dlg_title,num_lines,def);
%// Transform the strings into numbers that you can use.
Gender = answer{1};
Age = str2double(answer{2});
RHR = str2double(answer{3});
INTEN = answer{4};
%// A switch/case statement to convert INTEN into the number used for
%// the calculation
switch INTEN
case 'low'
INTEN=0.55;
case 'medium'
INTEN=0.65;
case 'high'
INTEN=0.8;
end
%// Use strcmp to compare strings.
if strcmp(Gender,'Male') || strcmp(Gender,'male')
THR=(220-Age-RHR)*INTEN+RHR;
elseif strcmp(Gender,'Female') || strcmp(Gender,'female')
THR=((06-0.88*Age)-RHR)*INTEN+RHR;
end
%// Create a string to display
DispMessage = sprintf('The recommended training heart rate is %0.2f\n',THR);
%// Create a message box to display the above string.
msgbox(DispMessage)
以下是提示窗口的样子:
并显示消息:
希望有所帮助!
答案 1 :(得分:0)
Matlab无法弄清楚你给出的是什么。正确的版本是:
Gender=input('Please input your gender: ','s');
此外,您的代码中还有更多错误,我建议您自行修复。我的不太先进的版本然后abowe:
Gender=input('Please input your gender: ','s');
Age=input('Please input your age: ');
RHR=input('Please enter your resting heart rate: ');
INTEN=input('Please enter your fitness level(low,medium or high): ','s');
if strcmp(INTEN,'low')
INTENT=0.55;
elseif strcmp(INTEN,'medium')
INTEN=0.65;
else
INTEN=0.8;
end
if strcmp(Gender,'male')|| strcmp(Gender,'Male')
THR=((220-Age)-RHR)*INTEN+RHR;
if strcmp(Gender,'female')|| strcmp(Gender,'Female')
THR=((206-0.88*Age)-RHR)*INTEN+RHR;
end
printres=['The recommended training heart rate is ',num2str(THR)];
disp(printres)