Question

表作者：

id | name_author
---------
1 | david
2 | kate
3 | tom
4 | mark

表格书：

id | name_book
------------
1 | book1
2 | book2
3 | book3

表关系作者和书籍

id_book | id_author
-------------------
1 | 2
1 | 3
1 | 4
2 | 2
1 | 1
3 | 4

因此，我必须得到“Book1”这本书，因为它有4位作者（大卫，凯特，汤姆，马克）。

如何向mysql写一个查询？

Answer 1

你可以写出类似的东西（未经测试）

select name_book
from books as b
, link_book_author as l
where b.id = l.id_book
group by name_book
having count(id_author) = 4

Answer 2

简单如下：

SELECT COUNT(DISTINCT(id_author)) as authors_num,id_book
FROM table1
GROUP BY id_book
HAVING authors_num=4

如果您需要书名：

SELECT COUNT(DISTINCT(table1.id_author)) as authors_num,
  table1.id_book, 
  books.name_book
FROM table1
LEFT JOIN books
ON books.id = table1.book_id
GROUP BY id_book
HAVING authors_num=4

Answer 3

也许吧：

SELECT b.name_book, a.name_author
FROM relationships r
JOIN books b ON r.id_book = b.id
JOIN author a ON r.id_author = a.id
WHERE b.name_book = 'Book1'
;

结果：

+-----------+-------------+
| name_book | name_author |
+-----------+-------------+
| book1     | kate        |
| book1     | tom         |
| book1     | mark        |
| book1     | david       |
+-----------+-------------+
4 rows in set (0.00 sec)

或者：

SELECT b.name_book, GROUP_CONCAT(a.name_author) authors
FROM relationships r
JOIN books b ON r.id_book = b.id
JOIN author a ON r.id_author = a.id
WHERE b.name_book = 'Book1'
;

结果：

+-----------+---------------------+
| name_book | authors             |
+-----------+---------------------+
| book1     | kate,tom,mark,david |
+-----------+---------------------+
1 row in set (0.00 sec)

Answer 4

SELECT
    b.name_book, GROUP_CONCAT(a.name_author) authors
FROM relationships r
JOIN books b ON r.id_book = b.id
JOIN author a ON r.id_author = a.id
GROUP BY r.id_book
HAVING COUNT(r.id_book) = 4
;

从表中选择那些只有4位作者的书？

4 个答案: