Question

我的数据库中有一个名为MyFolder的多层对象。 MyFolder可以是无限级别的另一个MyFolder的孩子。该表定义如下：

CREATE TABLE dbo.MyFolders
(
    MyFolderId INT IDENTITY(1,1) NOT NULL,
    ParentMyFolderId INT NULL,
    Name NVARCHAR(50) NOT NULL,
    Depth INT NOT NULL,
    Ancestry NVARCHAR(max) NOT NULL,
    CONSTRAINT PK_MyFolders PRIMARY KEY CLUSTERED (MyFolderId ASC),
    CONSTRAINT FK_MyFolders_MyFolders FOREIGN KEY(ParentMyFolderId) REFERENCES dbo.MyFolders (MyFolderId)
)

它有如下数据：

MyFolderId ParentMyFolderId Name           Depth Ancestry
1          NULL             Folder1        0     /
2          1                Folder1A       1     /1/
3          1                Folder1B       1     /1/
4          1                Folder1C       1     /1/
5          4                Folder1C1      2     /1/4/
6          4                Folder1C2      2     /1/4/
7          6                Folder1C2a     3     /1/4/6/
8          6                Folder1C2b     3     /1/4/6/

这对我系统中所需的一切都很有效。但是，如果我想要检索如下的查询，那就很棘手了：

MyFolderId Name
1          Folder1
2          Folder1/Folder1A
3          Folder1/Folder1B
4          Folder1/Folder1C
5          Folder1/Folder1C/Folder1C1
6          Folder1/Folder1C/Folder1C2
7          Folder1/Folder1C/Folder1C2/Folder1C2a
8          Folder1/Folder1C/Folder1C2/Folder1C2b

有没有办法在祖先字段上加入以获取祖先的名字？或者使用ParentMyFolderId列的另一种方式？我有一个表值拆分字符串函数，名为SplitString（value，delimiter）。

Answer 1

这可以使用递归查询来完成，只需将您当前的文件夹名称附加到之前的文件夹中即可。

<强>查询：

;WITH Source (MyFolderId, ParentMyFolderId, Name, Depth, Ancestry)
AS (
SELECT 1, NULL, 'Folder1', 0, '/'
UNION ALL
SELECT 2, 1, 'Folder1A', 1, '/1/'
UNION ALL
SELECT 3, 1, 'Folder1B', 1, '/1/'
UNION ALL
SELECT 4, 1, 'Folder1C', 1, '/1/'
UNION ALL
SELECT 5, 4, 'Folder1C1', 2, '/1/4/'
UNION ALL
SELECT 6, 4, 'Folder1C2', 2, '/1/4/'
UNION ALL
SELECT 7, 6, 'Folder1C2a', 3, '/1/4/6/'
UNION ALL
SELECT 8, 6, 'Folder1C2b', 3, '/1/4/6/'
),
cte AS
(
SELECT S.MyFolderID, S.ParentMyFolderId, CAST(S.Name AS VARCHAR(MAX)) AS Name
FROM Source AS S
WHERE ParentMyFolderId IS NULL
UNION ALL
SELECT S.MyFolderID, S.ParentMyFolderId, C.Name + '/' + S.Name
FROM Source AS S
INNER JOIN cte AS C
    ON C.MyFolderId = S.ParentMyFolderId
)
SELECT *
FROM cte

Answer 2

这里是评论中提到的递归CTE：

WITH TreeStructure(MyFolderId, Name) AS 
(
    SELECT MyFolderId, CONVERT(varchar(500), Name)
    FROM MyFolders WHERE ParentMyFolderId IS NULL
    UNION ALL
    SELECT sd.MyFolderId, CONVERT(varchar(500), t.Name + '/' + sd.Name)
    FROM MyFolders sd
    JOIN TreeStructure t ON sd.ParentMyFolderId = t.MyFolderId
    WHERE sd.ParentMyFolderId IS NOT NULL
)
SELECT * FROM TreeStructure

结果：

MyFolderId  Name
----------- ----------------------------------------
1           Folder1
2           Folder1/Folder1A
3           Folder1/Folder1B
4           Folder1/Folder1C
5           Folder1/Folder1C/Folder1C1
6           Folder1/Folder1C/Folder1C2
7           Folder1/Folder1C/Folder1C2/Folder1C2a
8           Folder1/Folder1C/Folder1C2/Folder1C2b

SQL JOIN列中的ID列表

2 个答案: