Question

我试图编写一个代码，只需输入你的测试分数（满分100分），它就会给你一个分数（A，B，C，D ..等）。但是，由于某种原因，我写的代码在给出一个随机数时给了我错误的分数。例如，我键入6，它给了我一个D（而不是U）。这是我的代码：

score=int(input("What score did you get on your test?"))

if int(0)>=score<=int(39):   
    print ("You have got a U in your test.")
elif int(40)>=score<=int(49):    
    print ("You have got a D in your test.")
elif int(50)>=score<= int(59):  
    print ("You have got a C in your test.")
elif int(60)>=score<= int(69):    
    print ("You have got a B in your test.")
else:
    ("You have got an A in your test, well done!")

Answer 1

你的不平等是不正确的。目前，U的条件是

if score is smaller than 0 and smaller than 39

应该是

if score is greater than 0 and smaller than 39

所以

if int(0) <= score <= int(39)

但是，正如其他人所指出的那样，您可以大量简化所有代码。您可以远程处理双边不等式并将其替换为单个不等式，删除int条件，因为您不期望任何非整数（数字39,49等都是硬编码的），您还应该为0以下或100以上的等级添加某种错误消息（目前，它们分别返回U和A，但它确实应该是错误的。）

更好的解决方案：

score=int(input("What score did you get on your test?"))

if score < 0:
    print("How did you manage to get less than zero?!")
elif score <= 39:
    print ("You have got a U in your test.")
elif score <= 49:    
    print ("You have got a D in your test.")
elif score <= 59:  
    print ("You have got a C in your test.")
elif score <= 69:    
    print ("You have got a B in your test.")
elif score <= 100:
    print ("You have got an A in your test, well done!")
else
    print ("This isn't a valid grade, it should be between 0 and 100!")

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