Question

我不知道我做错了什么，但我的python代码中的函数.lower（）无效！

这是一个狡猾的代码，但它并没有降低单词的含义：

score = {"a": 1, "c": 3, "b": 3, "e": 1, "d": 2, "g": 2, 
         "f": 4, "i": 1, "h": 4, "k": 5, "j": 8, "m": 3, 
         "l": 1, "o": 1, "n": 1, "q": 10, "p": 3, "s": 1, 
         "r": 1, "u": 1, "t": 1, "w": 4, "v": 4, "y": 4, 
         "x": 8, "z": 10}

def scrabble_score(word):
    word.lower()
    print word
    total =0
    for i in word:
        total += score[i]
    return total

print scrabble_score('Helix')

一些帮助？

Answer 1

您必须将lower()的结果分配给单词，因为字符串为immutable：

In [152]:

score = {"a": 1, "c": 3, "b": 3, "e": 1, "d": 2, "g": 2, 
         "f": 4, "i": 1, "h": 4, "k": 5, "j": 8, "m": 3, 
         "l": 1, "o": 1, "n": 1, "q": 10, "p": 3, "s": 1, 
         "r": 1, "u": 1, "t": 1, "w": 4, "v": 4, "y": 4, 
         "x": 8, "z": 10}

def scrabble_score(word):
    word = word.lower() #<------ here assign back
    print(word)
    total =0
    for i in word:
        total += score[i]
    return total

print(scrabble_score('Helix'))

helix
15

参见相关内容：Why are Python strings immutable? Best practices for using them

Answer 2

执行：

word = word.lower()

因为lower()没有修改原始字符串

Answer 3

这是因为在将其转换为小写后，您没有为单词赋值。所以它仍然具有旧的价值，即＆＃34; Helix＆＃34;

word = word.lower()

python .lower（）不起作用

3 个答案: