Question

任何人都可以帮助我，我想建立一个搜索页面，将所有数据从value1输出到value2。我得到这个错误警告：mysql_num_rows（）期望参数1是资源，

Search.php表格

<form action="Search.php" method="POST">
<input type="text" name="value1" placeholder="FROM TIME">
<input type="text" name="value2" placeholder="TO TIME">
<input type="submit" value=">>">
</form>

的search.php

<?php 
 mysql_connect("localhost","root","") or die("NO connection");
  mysql_select_db("ci")or die("No DATABASE");
  $value1 =$_POST['value1'];
 $value2 =$_POST['value2'];
 $output="";
 if (isset($_POST ['value1'],$_POST['value2'])){
 $result=mysql_query("SELECT * FROM slogs WHERE TIME BETWEEN
 ".$_POST['value2']." AND ".$_POST['value2']." ");
  $count=mysql_num_rows($result);
 if($count==0){
   $output='You are not a student';
  } else{
 while($row=mysql_fetch_array($result))
        {
    echo "<tr>";
    echo "<td>".$TIME.=$row['TIME']."</td>";
    echo "<td>".$FN.=$row['FN']."</td>";
    echo "<td>".$LN.=$row['LN']."</td>";
    echo "<td>".$DT.=$row['DT']."</td>";
    echo "</tr>";


        }
     }
     }
    ?>

Answer 1

您的搜索正在选择相同的两个值之间的数据。试试这个：

<?php 
 mysql_connect("localhost","root","") or die("NO connection");
  mysql_select_db("ci")or die("No DATABASE");
  $value1 =$_POST['value1'];
 $value2 =$_POST['value2'];
 $output="";
 if (isset($value1,$value2)){
 $result=mysql_query("SELECT * FROM slogs WHERE TIME BETWEEN
 ". $value1 ." AND ". $value2 ." ");
  $count=mysql_num_rows($result);
 if($count==0){
   $output='You are not a student';
  } else{
 while($row=mysql_fetch_array($result))
        {
    echo "<tr>";
    echo "<td>".$TIME.=$row['TIME']."</td>";
    echo "<td>".$FN.=$row['FN']."</td>";
    echo "<td>".$LN.=$row['LN']."</td>";
    echo "<td>".$DT.=$row['DT']."</td>";
    echo "</tr>";


        }
     }
     }
    ?>

Answer 2

尝试在您查询的值周围添加单引号'

$result=mysql_query("SELECT * FROM slogs WHERE TIME BETWEEN '". $value1 ."' AND '". $value2 ."' ");

请帮我把数据从value1输出到value2

2 个答案: