Question

我一直在尝试几种方法来删除一些元素，似乎无法让它工作。该计划需要[]和,。我试过nums.remove(x)。

  import random
  ROWS = 7
  COLS = 1

  def main():
      nums = [0, 0, 0, 0, 0, 0, 0]
      for r in range(ROWS):
          nums[r] = random.randint(20, 80)
      nums = [int(r) for r in nums]
      print(nums)
      print('The largest integer is',max(nums))
      print('The lowest integer is',min(nums))
      nums.sort()
      print('The middle 5 sorted low to high',nums, )


  main()

期望的输出：

79 30 39 33 41 43 53 
The highest number is 79
The lowest number is 30
The middle 5 sorted high to low:
43 41 39 33 30

当前输出：

[22, 35, 39, 24, 75, 24, 33] 
The largest integer is 75 
The lowest integer is 22 
The middle 5 sorted low to high [22, 24, 24, 33, 35, 39, 75]

Answer 1

您可以使用列表解析打印带空格分隔的列表：

print(' '.join([str(x) for x in nums]))

您可以使用切片表示法获取数组的中间5个元素：

print('The middle 5 sorted low to high', ' '.join([str(x) for x in nums[1:-1]))

Answer 2

你可以，但需要更多时间。打印如下列表：

my_lst = ['0', '0', '0', '0']
print(my_lst)

将产生所需的结果加上括号：

[0, 0, 0, 0]

要删除括号并将数字放在新行中，您可以尝试在新行上分别打印所有数字：

...
print(nums[0], nums[1], nums[2], nums[3], nums[4])

或使用while循环加上变量：

num = 0
while num < len(nums):
    num += 1
    print(nums[num])

不幸的是，它最终会在一条线上下降，而不是从左到右。我希望这回答了你的问题！

Answer 3

也许您可以使用list.pop删除列表中最大和最低的nums：

import random
ROWS = 7
COLS = 1

def main():
  nums = [0, 0, 0, 0, 0, 0, 0]
  for r in range(ROWS):
    nums[r] = random.randint(20, 80)
    nums = [int(r) for r in nums]
  largest = max(nums)
  lowest = min(nums)
  print(nums)
  print('The largest integer is',largest)
  print('The lowest integer is',lowest)
  nums.sort()
  nums.pop(0) # remove first
  nums.pop(-1) # remove last
  print('The middle 5 sorted low to high',nums)


main()

或者用这种方式删除：

import random
ROWS = 7
COLS = 1

def main():
  nums = [0, 0, 0, 0, 0, 0, 0]
  for r in range(ROWS):
    nums[r] = random.randint(20, 80)
    nums = [int(r) for r in nums]
  largest = max(nums)
  lowest = min(nums)
  print(nums)
  print('The largest integer is',largest)
  print('The lowest integer is',lowest)
  nums.sort()
  nums.remove(largest)
  nums.remove(lowest)
  print('The middle 5 sorted low to high',nums)


main()

如果列表中有多个最大或最低的nums，请尝试以下函数：

def remove_largest_lowest(alist):
  return [i for i in alist if i not in (max(alist),min(alist))]
print remove_largest_lowest([1,1,2,3,1,5,5])

Answer 4

不适用于积分。

如果您知道正确的库，您可以使您的代码简洁明了。当然，这是矫枉过正，但是，嘿，总是有趣的是有一个替代的答案。在我的回答中，我将使用numpy生成随机整数。事实证明，这比for循环要容易得多。

import numpy as np

ROWS = 7

def main():

    nums = np.random.randint(20,80,ROWS)
    print " ".join([str(n) for n in nums])
    print "The largest integer is {}.".format(nums.max())
    print "The smallest integer is {}.".format(nums.min())
    print "The middle {} sorted low to high are {}.".format(ROWS - 2, ", ".join([str(n) for n in sorted(nums)[1:-1]]))

main()

这样可以运行以下示例：

50 51 78 41 58 37 38
The largest integer is 78.
The smallest integer is 37.
The middle 5 sorted low to high are 38, 41, 50, 51, 58.

随机整数，删除元素

4 个答案: