public function getAvailableVideosByRfid($rfid, $count=200) {
$query="SELECT id FROM sometable WHERE rfid='$rfid'";
$result = mysql_query($query);
$count2 = mysql_num_rows($result);
if ($count2){ //this rfid has been claimed
return 0;
}
我的断言是: 1)。 $ rfid是一个长度为5个字符的字符串 2)。我得到了一个有效的结果集
谢谢
请假设我有以下单元测试代码:
class videoSharingTest extends PHPUnit_Framework_TestCase {
/**
* @var videoSharing
*/
protected $object;
/**
* Sets up the fixture, for example, opens a network connection.
* This method is called before a test is executed.
*/
protected function setUp() {
$this->object = new videoSharing;
}
/**
* Tears down the fixture, for example, closes a network connection.
* This method is called after a test is executed.
*/
protected function tearDown() {
}
public function testGetAllVideosByRfid(){
******我应该把这里放什么*****
}
答案 0 :(得分:1)
您需要分散数据库,通常使用您要模拟的数据库抽象层。因此,在具有您正在使用的方法的对象上添加 - > gt。setDatabase()等。然后在setUp(){...}中,你将Database对象设置为mock:
$this->object->setDatabase($mockDb);
然后你会改变
$ result = mysql_query($ query); $ count2 = mysql_num_rows($ result);
使用某种形式的PDO - 以便您可以使用PDO Sql Lite调用setDatabase()。例如:
setUp() { $this->object->setDatabase($mockDb); }
testFunction() {
$rfid = 'the rfid to use in the test';
//make sure no videos exist yet
$this->assertEquals(0, count($this->object->getAvailableVideosByRfid($rfid, ..);
//you may want to assert that it returns a null/false/empty array/etc.
$db = $this->object->getDatabase();
$records = array(... some data ...);
$db->insert($records); //psuedo code
$vids = $this->object->getAvailableVideosByRfid($rfid, ..); //however you map
$this->assertEquals(count($records), count(vids));
foreach($vids as $video) {
//here you would map the $video to the corresponidng $record to make sure all
vital data was stored and retrieved from the method.
}
}
通常,这将全部在PDO Sqlite中完成,因此不会为单元测试而创建/创建真正的数据库。它会在测试中生存和死亡,任何地方的开发人员都可以在没有配置的情况下使用它。