这是我的登录页面:
“这是表格,表格动作=”“设置为无(可能是问题?)
< form action =“”method =“POST”>
用户名:< input type =“text”name =“user”>
密码:< input type =“password”name =“pass”>
< input type =“submit”value =“Login”name =“submit”/>
< /形式>“中
$query=mysql_query("SELECT * FROM login WHERE username='".$user."' AND password='".$pass."'");
$numrows=mysql_num_rows($query);
if($numrows!=0)
{
while($row=mysql_fetch_assoc($query))
{
$dbusername=$row['username'];
$dbpassword=$row['password'];
}
if($user == $dbusername && $pass == $dbpassword)
{
session_start();
$_SESSION['sess_user']=$user;
/* Redirect browser */
header("Location: member.php");
}
} else {
echo "Invalid username or password!";
}
第二页
<?php
session_start();
if(!isset($_SESSION["sess_user"])){
header("location:login.php");
} else {
每当我点击“登录”按钮时,表单会返回而不是重定向我的页面..请帮助,
提前致谢
答案 0 :(得分:0)
为什么不试试这样:
<?php
session_start();
$query = mysql_query("SELECT * FROM login WHERE username='" . $user . "' AND password='" . $pass . "'");
$numrows = mysql_num_rows($query);
if ($numrows > 0) {
while ($row = mysql_fetch_assoc($query)) {
$dbusername = $row['username'];
$dbpassword = $row['password'];
}
$_SESSION['sess_user'] = $user;
header("Location: http://peopleinvestment.ro/filip/member.php");
} else {
echo "Invalid username or password!";
}
它也更智能和更短,因为如果用户名和密码匹配
,则检查2次答案 1 :(得分:0)
我实际上找到了另一种方式:
基本上:
echo "<script>
top.location='admin.php'
</script>"
答案 2 :(得分:-1)
我认为header()引发了很多错误。所以我使用的是:
<meta http-equiv='refresh' content="0; url=yoururlhere"
保持原样,它会将您重定向到新页面:)与标题相同。这应该可以解决你的问题。
修改强>
好的,这里有一些更新有助于提高安全性,它应该可以解决您的问题! :) 首先让我们从数据库连接文件开始:
<?php
$db_username = ""; //Input your database username here
$db_password = ""; //Input your database password here
$db_host = ""; //Input your database host here
$db_name = ""; //Input your database name here
$options = array(PDO::MYSQL_ATTR_INIT_COMMAND => 'SET NAMES utf8');
try {
$connection = new PDO("mysql:host={$db_host};dbname={$db_name};charset=utf8", $db_username, $db_password, $options);
$connection->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
}
catch(PDOException $ex) {
echo "Can not connect to database.";
}
header('Content-Type: text/html; charset=utf-8');
?>
以上将为您连接到您的数据库! :) 好的,接下来让我们使用PHP(请在输入之前将它放在您的顶部):
<?php
//Grabs the database connection
require("path to database connection file");
$user = $_POST["user"];
$pass = $_POST["pass"];
$query="SELECT * FROM login WHERE username=:username AND password=:password";
$params->execute(array(':username' => $user,
':password' => $pass));
try{
$stmt = $connection->prepare($query);
$result = $stmt->execute($params);
}
catch(PDOException $ex){
echo ("Failed to run query: " . $ex->getMessage());
}
$fetch = $stmt->fetch();
if($fetch) {
while($row=mysql_fetch_assoc($query)){
$usernamefetch=$fetch['username'];
$passwordfetch=$fetch['password'];
}
if($user == $usernamefetch && $pass == $passwordfetch)
session_start();
$_SESSION['sess_user']=$user;
?>
<meta http-equiv='refresh' content="0; url=page_to_redirect_to"
<?php
{
else {
echo "Invalid username or password!";
}
}
else {
echo "Invalid username or password!";
}
?>
这就是代码,它应该完美无缺! :)你唯一应该确保改变的是重定向到哪里的mets标签。当然,你的简单HTML:
<form action="" method="POST">
Username: <input type="text" name="user">
Password: <input type="password" name="pass">
<input type="submit" value="Login" name="submit" />
</form>
请测试一下这段代码,我认为它现在会更好用! :)更不用说它会更加安全。
修改强>
最后,我让这个100%工作! :)好了,现在用这个:
<?php
$db_username = "peoplein"; //Input your database username here
$db_password = "xxxxxxx"; //Input your database password here
$db_host = "localhost"; //Input your database host here
$db_name = "xxxxxxxx"; //Input your database name here
$options = array(PDO::MYSQL_ATTR_INIT_COMMAND => 'SET NAMES utf8');
try {
$connection = new PDO("mysql:host={$db_host};dbname={$db_name};charset=utf8", $db_username, $db_password, $options);
$connection->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
}
catch(PDOException $ex) {
echo "Cannot connect to database.";
}
header('Content-Type: text/html; charset=utf-8');
?>
<!doctype html>
<html>
<head>
<title>Login</title>
</head>
<body>
<?php
if (isset($_POST["user"])) {
$user = $_POST["user"];
}
else {
$user = "";
}
if (isset($_POST["pass"])) {
$pass = $_POST["pass"];
}
else {
$pass = "";
}
$query="SELECT * FROM login WHERE username=:username";
$params=(array(':username' => $user));
try{
$stmt = $connection->prepare($query);
$result = $stmt->execute($params);
}
catch(PDOException $ex){
echo ("Failed to run query: " . $ex->getMessage());
}
$fetch = $stmt->fetch();
$passwordfetch=$fetch['password'];
if (password_verify($pass, $passwordfetch)) {
session_start();
$_SESSION['sess_user']=$user;
?>
<meta http-equiv='refresh' content="0; url=http://peopleinvestment.ro/filip/admin.php">
<?php
}
else {
echo "Invalid Information";
}
?>
<center>
<h3>Login</h3>
<form action="" method="POST">
Username: <input type="text" name="user">
Password: <input type="password" name="pass">
<input type="submit" value="Login" name="submit" />
</form>
</body>
</html>
请勿更改任何内容,而是更改db_password和db_name。接下来你应该改变的事情。首先,如果有人进入您的数据库,您的密码不安全,因为它们没有“哈希”。现在,您可以在将这些密码提交到数据库之前执行此操作来散列这些密码:
password_hash($pass, PASSWORD_DEFAULT);
所以基本上在用户即将注册之前它会自动password_hash,然后将其输入到数据库中。现在必须完成,否则上面的代码将无效。然而,如果您选择不使用password_hash(糟糕的主意),那么您可以使用此代码:http://pastebin.com/SJisBwnB。这应该可以解决您的问题,如果仍有任何错误,或者您有任何疑问,请再发表评论! :)这对我来说很完美。