Question

我注意到这已被问过几次，但我找不到有效的答案。我正在编写一个类来处理我的数据库调用，并且由于某种原因无法建立连接。

这是我收到的错误：

警告：mysqli :: mysqli（）:( 28000/1045）：拒绝访问用户＆root;＆＃39; @＆＃39; localhost＆＃39; （在...中使用密码：是）

这是尝试创建类实例的代码：

    <?php
    require_once 'inventoryconfig.php';
    require("MySQLiClass.inc");
    ini_set('display_errors',1);  error_reporting(E_ALL);

    echo "control";

    /* works */
    $connection = new mysqli($db_hostname, $db_username, $db_password, $db_database, $db_port);
        if ($connection->connect_error) die($connection->connect_error);            

    /* doesn't */   
    $mysqli_db = new mysqli_db($db_hostname, $db_username, $db_password, $db_database, $db_port);

    ?>

这是班级：

<?php
require_once 'IRCinventoryconfig.php';
require("drawTable.inc");
ini_set('display_errors',1);  error_reporting(E_ALL);


    class mysqli_db 
    {
        protected $db_hostname;
        protected $db_database;
        protected $db_username;
        protected $db_password;
        protected $db_port;
        protected $connection; 


        function __construct($db_hostname, $db_database, $db_username, $db_password, $db_port)
        {
            $this->db_hostname = $db_hostname;
            $this->db_database = $db_database; 
            $this->db_username = $db_username;
            $this->db_password = $db_password;
            $this->db_port     = $db_port;

            if    (!empty($db_hostname)
                || !empty($db_database)
                || !empty($db_username)
                || !empty($db_password)
                || !empty($db_port))
            {
                $this->_connect();
            } else {
                die("You did not provide enough information, please check your configuration files and try again.");
            }

        }

        public function _connect()
        {
                /* echoes the correct information */
                echo $this->db_hostname;
                echo $this->db_database;
                echo $this->db_username;
                echo $this->db_password;
                echo $this->db_port;

            $this->connection = new mysqli($this->db_hostname, $this->db_username, $this->db_password, $this->db_database, $this->db_port)
            or die("Database access failed:" . $this->connection->error);
            //$this->connection = new mysqli($this->db_hostname, $this->db_username, $this->db_password, $this->db_database, $this->db_port);
            //if ($this->connection->connect_error) die($this->connection->connect_error);
        }
    }

Answer 1

您的参数以不正确的顺序提供给构造函数。

$mysqli_db = new mysqli_db($db_hostname, $db_username, $db_password, $db_database, $db_port);

function __construct($db_hostname, $db_database, $db_username, $db_password, $db_port)

构造函数应该如下所示：

function __construct($db_hostname, $db_username, $db_password, $db_database, $db_port)

Answer 2

首先，所有参数都需要保存一个值：

if    (!empty($db_hostname)
            || !empty($db_database)
            || !empty($db_username)
            || !empty($db_password)
            || !empty($db_port))
        {

听起来不对。我建议

if    (!empty($db_hostname)
            && !empty($db_database)
            && !empty($db_username)
            && !empty($db_password)
            && !empty($db_port))
        {

...并且传递给构造的参数的顺序是错误的。它必须遵循mysqli构造顺序（主机，用户，通道，数据库，端口）

警告：mysqli :: mysqli（）:( 28000/1045）：访问被拒绝

2 个答案: