Question

我想在bootstrap缩略图中显示一些数据。我不明白为什么它不显示从数据库中提取的任何数据。数据库连接是正确的。

<div class="jumbotron">
	<div class="container">
		<center>
		<h1> Welkom!</h1>
		 <p>Op de website van Ter Bruggen Antiek en Curiosa.<br />Voor uw mooiste antieke kroonluchters, lampen, meubelen en overige producten.</p>
			<p><a class="btn btn-primary btn-lg disabled" href="?page=info" role="button">Meer weten?</a></p>
		</center>
	</div>
</div>
<div class="container">
	<center>
		<h2>Uitgelicht!</h2>
	</center>
		<div class="row">
			<?php
				$sql = "SELECT * FROM advertentie, categorie WHERE advertentie.categorie_id = categorie.categorie_id AND uitgelicht=1";
				$result = $connect->query($sql);
				
				if ($result->num_rows > 0){
					while ($row = $result -> fetch_assoc()){
						echo   "<div class='col-lg-3'>";
						echo     "<div class='thumbnail'";
						echo     "<img class='img-square img-responsive' src='../img/uploads/".$row['filename']."'/> ";
						echo     	"<div class='caption'>";
						echo 			"<h4>".$row['advertentietitel']."</h4>";
						echo 			"<p>".$row['categorie_naam']."</p>";
						echo 			"<p>".$row['verkooprijs']."</p>";
						echo 			"<p><a href='?page=details&id=".$row['advertentie_id']." class='btn btn-primary'>Bekijk</a></p>";
						echo 		"</div>";
						echo 	 "</div>";
						echo   "</div>";
					}
				}
			?>
		</div>	
</div>

Answer 1

您的选择查询不正确。你应该使用mysql的JOIN。我不知道你的数据库结构。如果您显示数据库结构，那么我可以帮助您。请尝试以下查询并分享结果

$sql = "SELECT advertentie.* FROM advertentie LEFT OUTER JOIN categorie on  advertentie.categorie_id = categorie.categorie_id WHERE advertentie.uitgelicht=1";

不在引导程序缩略图中生成数据

1 个答案: