我有一些用PHP编写的日历,带有上一个和下一个按钮。现在我想使用一些ajax转到上一个或下一个日期而不刷新页面。
在ajax调用的php文件中,我有一个查询,它返回选定日期的任务(类似于:...WHERE date = $date
)。
问题在于我无法到达今天前一天等等,以及今天的后一天等等。
有人可以提供帮助吗?
修改
按钮:
<button class='btn btn-default previous' data-date='$date'>
<span class='glyphicon glyphicon-arrow-left' aria-hidden='true'></span>
</button>
<button class='btn btn-default next' data-date='$date'>
<span class='glyphicon glyphicon-arrow-right' aria-hidden='true'></span>
</button>
Jquery的:
$(document).ready(function() {
$('button.previous').click(function() {
var date = $(this).data('date');
$.ajax({
type: "POST",
data: { action : "previous" , date: date },
url: "includes/ajax/plannerdata.php",
success: function(returnData){
$("#planner-data").html(returnData);
}
});
});
$('button.next').click(function() {
var date = $(this).data('date');
$.ajax({
type: "POST",
data: { action: 'next', date: date },
url: "includes/ajax/plannerdata.php",
success: function(returnData){
$("#planner-data").html(returnData);
}
});
});
});
plannerdata.php:
switch ($_POST['action']) {
case 'next':
$date = strftime('%Y-%m-%d', strtotime($_POST['date'] .' -1 day'));
break;
case 'previous':
$date = strftime('%Y-%m-%d', strtotime($_POST['date'] .' +1 day'));
break;
}
然后我在查询中使用$ date。
UPDATED plannerdata.php:
if (!isset ($_POST['date'])) { // At first page load or refresh (without using the previous/next buttons), plannerdata.php is also loaded bij ajax and injected in index.php
$currentDatetime = new DateTime('NOW');
}
else { // Previous or next button is pressed
$currentDatetime = new DateTime($_POST['date']);
}
$dateModification = $_POST['action'];
switch ($dateModification) {
case 'previous':
$currentDatetime->modify('-1 day');
break;
case 'next':
$currentDatetime->modify('+1 day');
break;
}
$date = $currentDatetime->format('Y-m-d');
修改
plannerdata.php;
if (!isset ($_SESSION['date'])) {
$_SESSION['date'] = new DateTime('NOW');
}
if (isset ($_POST['action'])) {
switch ($_POST['action']) {
case 'previous':
$_SESSION['date']->modify('-1 day');
break;
case 'next':
$_SESSION['date']->modify('+1 day');
break;
}
}
$date = $_SESSION['date']->format('Y-m-d');
按钮(在index.php中)。我删除了data-date属性:
<button class='btn btn-default previous'><span class='glyphicon glyphicon-arrow-left' aria-hidden='true'></span></button>
<button class='btn btn-default next'><span class='glyphicon glyphicon-arrow-right' aria-hidden='true'></span></button>
按钮位于两个按钮内部,并显示所选日期。
<ul>
<li>button previous</li>
<li><span id="planner_date">selected date</span></li>
<li>button next</li>
<ul>
我也改变了Jquery。我同时进行ajax通话。
$(document).ready(function() {
$('button.previous').click(function() {
$.when(
$.post("includes/ajax/plannerdata.php", {action: 'previous'}, function(data) {
plannerData = data;
}),
$.post("includes/ajax/date.php", {action: 'previous'}, function(date) {
calendardate = date;
})
).then(function() {
$("#planner-data").html(plannerData);
$("#planner_date").text(calendardate);
});
});
$('button.next').click(function() {
$.when(
$.post("includes/ajax/plannerdata.php", {action: 'next'}, function(data) {
plannerData = data;
}),
$.post("includes/ajax/date.php", {action: 'next'}, function(date) {
calendardate = date;
})
).then(function() {
$("#planner-data").html(plannerData);
$("#planner_date").text(calendardate);
});
});
});
返回当前日期的Date.php:
if (!isset ($_SESSION['current_date'])) {
$_SESSION['current_date'] = new DateTime('NOW');
}
if (isset ($_POST['action'])) {
switch ($_POST['action']) {
case 'previous':
$_SESSION['current_date']->modify('-1 day');
break;
case 'next':
$_SESSION['current_date']->modify('+1 day');
break;
}
}
$date = $_SESSION['current_date']->format('Y-m-d');
echo $date;
编辑2015-03-05:
Jquery的:
$(document).ready(function() {
$('button.previous').click(function() {
$.when(
$.post("includes/ajax/date.php",
{action: 'previous'},
function(date) {
dates = jQuery.parseJSON(date);
calendardate = dates.dutch;
$.post("includes/ajax/plannerdata.php",
{date: dates.sql},
function(data) {
plannerData = data;
})
})
).then(function(){
$("#planner_date").text(calendardate);
$("#planner-data").html(plannerData);
});
});
});
date.php
if (!isset ($_SESSION['current_date'])) {
$_SESSION['current_date'] = new DateTime('NOW');
}
if (isset ($_POST['action'])) {
switch ($_POST['action']) {
case 'previous':
$_SESSION['current_date']->modify('-1 day');
break;
case 'next':
$_SESSION['current_date']->modify('+1 day');
break;
}
}
$date_1 = $_SESSION['current_date']->format('Y-m-d');
$date_2 = $_SESSION['current_date']->format('d-m-Y');
$response = array('sql' => $date_1, 'dutch' => $date_2);
echo json_encode($response);
更新2015-03-08
$(document).ready(function() {
$('button.previous').click(function() {
var calendardate;
var plannerData;
$.when(
$.post("includes/ajax/date.php",
{action: 'previous'},
function(date) {
dates = jQuery.parseJSON(date)
calendardate = dates.dutch;
$.post("includes/ajax/plannerdata.php",
{date: dates.sql},
function(data) {
plannerData = data;
})}
)).then(function(){
$("#planner_date").text(calendardate)
$("#planner-data").html(plannerData);
});
});
});
答案 0 :(得分:1)
我可以看到,最适合您应该使用PHP DateTime。您可以将脚本修改为以下内容:
$dateModification=$_POST['action'];//for clarification
//Datetime understands every format strtotime does
$currentDatetime=new DateTime($_POST['date']);
switch ($dateModification) {
case 'next':
$currentDateTime->modify("+1 day");//simple, isn't it?
break;
case 'previous':
$currentDateTime->modify("-1 day");
break;
}
//final result
$date=$currentDateTime->format("Y-m-d");
使用DateTime,您可以轻松地将日期作为对象进行操作。也可以将两个Datetime对象与&lt; &GT; ==标志一样简单:
$firstDatetime=new Datetime("2015-02-20");
$secondDatetime=new Datetime("2015-02-25");
if ($firstDatetime<$secondDatetime)
{
echo '$firstDatetime was indeed first!';
}
自己尝试一下:)
编辑 - 如何在服务器端处理日期修改:
关于它的更多想法。您更新的代码正在对服务器进行两次AJAX调用,它们都在修改日期时间对象。因为它可以工作,它是重复的代码。让我们尝试修改调用和脚本以仅处理一个DateTime对象。我们将日期修改移至您的date.php
,plannerdata.php
将使用相同的日期变量。
<强>使用Javascript:强>
$(document).ready(function() {
$('button.previous').click(function() {
$.post("includes/ajax/date.php",
{action: 'previous'},
function(date) {
dates = jQuery.parseJSON(date)
$("#planner_date").text(dates.dutch)
$.post("includes/ajax/plannerdata.php",
{date: dates.sql},
function(data) {
$("#planner-data").html(data);
})
})
})
});
<强> PHP:强>
Date.php将保持不变,我们必须更改plannerdata.php以使用相同的变量:
//we remove that block, as it will be set in date.php
/*if (!isset ($_SESSION['date'])) {
$_SESSION['date'] = new DateTime('NOW');
}
if (isset ($_POST['action'])) {
switch ($_POST['action']) {
case 'previous':
$_SESSION['date']->modify('-1 day');
break;
case 'next':
$_SESSION['date']->modify('+1 day');
break;
}
}*/
$date = $_SESSION['current_date']->format('Y-m-d');
那应该是它! :)
如何从特定格式创建DateTime?:
出于此目的,存在函数DateTime::createFromFormat。用法示例:
setlocale(LC_TIME, "nl_NL");//firstly we need to setlocale, so month names will be properly recognized
$dateString='6 maart 2015';
$datetime=DateTime::createFromFormat("j F Y", $dateString);
这将返回datetime对象,您可以对其进行操作。
答案 1 :(得分:0)
使用INTERVAL,例如:
TOMORROW:
SELECT * FROM table WHERE date = $date + INTERVAL 1 DAY
YESTERDAY
SELECT * FROM table WHERE date = $date - INTERVAL 1 DAY