Question

我想清理一个包含字母数字（varchar2）记录的表格。应检查每个单个记录是否包含一组脏字，如果是，则应替换掉。模式和替换存储在单独的表中。

示例：

create table to_clean (
text_id number,
dirty_text  varchar2(4000));

insert into to_clean values(1,'hello this is my dirtyword1 text.');
insert into to_clean values(2,'hello this is my dirtyword3 text.');
insert into to_clean values(3,'hello this is my dirtyword2 dirtyword1  text.');

create table regex_list(
pattern varchar2(400),
replacement varchar2(400));

insert into regex_list values('dirtyword1','clean1');
insert into regex_list values('dirtyword2',' '); --remove totally
insert into regex_list values('dirtyword3','clean3');

伪代码：

for each dirty_text in to_clean
    for pattern, replacement in regexlist
        regex_replace(dirty_text, pattern, replacement)

在Oracle中解决此问题的最佳方法是什么？ regex_list包含正则表达式和普通字符串作为模式。我只想替换完整的单词，而不是部分单词（用空格分隔）

Answer 1

试试这个：

UPDATE to_clean c
   SET dirty_text =
          (SELECT REGEXP_REPLACE (dirty_text, pattern, replacement) replaced
             FROM    regex_list r
                  INNER JOIN
                     (SELECT t.*,
                             (SELECT pattern
                                FROM regex_list
                               WHERE INSTR (T.DIRTY_TEXT, pattern) <> 0)
                                find_pat
                        FROM to_clean t) s
                  ON (r.pattern = s.find_pat)
            WHERE c.dirty_text = dirty_text);

如果你有表达，而不是单词，instr不起作用，那么使用regexp_like（正如Justin Cave所说）：

SELECT REGEXP_REPLACE (dirty_text, pattern, replacement) replaced
             FROM    regex_list r
                  INNER JOIN
                     (SELECT t.*,
                             (SELECT pattern
                                FROM regex_list
                               WHERE regexp_like(T.DIRTY_TEXT,pattern) )
                                find_pat
                        FROM to_clean t) s
                  ON (r.pattern = s.find_pat)

修改

在这种情况下，您可以使用plsql。请看一下：

--Create oracle objects create or replace type clean_o as object(text_id number,dirty_text varchar2(500)); create or replace type clean_t as table of clean_o; --Function create or replace function clean_text return clean_t pipelined is cursor clean_c is select * from to_clean; text varchar2(250); begin for c in clean_c loop text:= c.dirty_text; for i in (select * from regex_list) loop text:= regexp_replace(text,i.pattern,i.replacement); end loop; PIPE ROW (clean_o(c.text_id,text)); end loop; end;

现在你可以这样做：

select * from table(clean_text)

Oracle - 通过正则表达式列表替换记录的子字符串

1 个答案: