Question

我有一个按钮，当我在EditText中键入一些数字时会做一堆东西。我想知道如何通过简单地按下＆＃34; Enter＆＃34;来触发这个按钮。键。现在我只有一个onClickListener，用户在将数据输入EditText后必须按下。我希望Button保留在那里并为用户提供额外的选项以便继续进行。

有人可以帮忙吗？下面的代码什么也没做。当我按下键盘上的Enter键时，它就转到下一行......

EditText.setOnEditorActionListener(new TextView.OnEditorActionListener() {
            @Override
            public boolean onEditorAction(TextView v, int actionId, KeyEvent event) {
                if ((event != null && (event.getKeyCode() == KeyEvent.KEYCODE_ENTER)) || (actionId == EditorInfo.IME_ACTION_DONE)){
                    Button.performClick();

                }
                return false;
            }
        });

Answer 1

此代码适用于我

youredittext.setOnEditorActionListener(new OnEditorActionListener() {
    public boolean onEditorAction(TextView v, int actionId, KeyEvent event) {
        if ((event != null && (event.getKeyCode() == KeyEvent.KEYCODE_ENTER)) || (actionId == EditorInfo.IME_ACTION_DONE)) {
            Log.i(TAG,"Enter pressed");
        }    
        return false;
    }
});

Answer 2

见：

     edittext.setOnKeyListener(new OnKeyListener(){
    public boolean onKey(View v, int keyCode, KeyEvent event) {     
            if ((event.getAction() == KeyEvent.ACTION_DOWN) && (keyCode == KeyEvent.KEYCODE_ENTER)) 
            {
               Toast.makeText(MainActivity.this,edittext.getText(), Toast.LENGTH_LONG).show();
               return true;
            }

Answer 3

请参阅下面的解决方案代码，

editText.setOnEditorActionListener(new TextView.OnEditorActionListener()
    {
        @Override
        public boolean onEditorAction(TextView textView, int id, KeyEvent keyEvent)
        {
            if (id == EditorInfo.IME_NULL)
            {
               //Do your button action here 

                return true;
            }
            return false;
        }
    });

如何在Android中按Enter键时触发按钮？

3 个答案: