Question

我的错误：

语法错误，意外＆＃39;＆＃39; SELECT * FROM成员＆＃39; C：\ xampp \ htdocs \ New文件夹中的（T_CONSTANT_ENCAPSED_STRING）（2）第63行\ loginexec.php

我已经尝试过：

$qry="SELECT * FROM members WHERE email='$login' AND password='$password'";

但仍有错误。我该如何解决这个问题？

＆＃13;

 
	$login = clean($_POST['user']);
	$password = clean($_POST['password']);
	
	//Create query
	mysql_query 'SELECT * FROM members WHERE email="$login" AND password="$password"';
	$(result=mysql_query($qry);
	//while($row = mysql_fetch_array($result))
//  {
//  $level=$row['position'];
//  }
	//Check whether the query was successful or not
	if($result) {
		if(mysql_num_rows($result) > 0) {
			//Login Successful
			session_regenerate_id();
			$member = mysql_fetch_assoc($result);
			$_SESSION['SESS_MEMBER_ID'] = $member['id'];
			$_SESSION['SESS_FIRST_NAME'] = $confirmation;
			
			session_write_close();
			//if ($level="admin"){
			header("location: order.php");
			exit();
			//}
			//else{
			//header("location: front.php");
			//exit();
			//}
		}else {
			//Login failed
			$errmsg_arr[] = 'Invalid Email add or password';
			$errflag = true;
			if($errflag) {
		$_SESSION['ERRMSG_ARR'] = $errmsg_arr;
		session_write_close();
		header("location: loginindex.php");
		exit();
	}
		}
	}else {
		die("Query failed");
	}

＆＃13;

Answer 1

您没有将查询分配给变量，您提供了

mysql_query 'SELECT * FROM members WHERE email="$login" AND password="$password"';

将查询分配给变量然后尝试..

$qry="SELECT * FROM members WHERE email=\"$login\" AND password=\"$password\"";

一旦尝试这个...... 我建议你使用mysqli或PDO，而不是mysql，不推荐使用coz mysql ...

Answer 2

尝试这样的事情：

$result = mysql_query("SELECT * FROM members WHERE email= '".$login."' AND password='".$password."'");

Answer 3

mysql_query是一个函数，因此您需要在括号之间包含参数：

$result = mysql_query(
    "SELECT * FROM members WHERE email='$login' AND password='$password'"
);

请记住：双引号（“）确实解析了像$ login和$ password这样的变量（你用mysql_real_escape_string吗？明确的功能不清楚，请注意）但是简单的引号（'）没有

祝你好运！

Answer 4

好吧，我不会使用我的密码，但似乎你需要使用2个参数制作mysql_query是mysql_query（数据库连接，查询）

我应该说开始学习mysqli而不是mysql

Answer 5

尝试此查询

$qry="SELECT * FROM members WHERE email=$login AND password=$password";

语法错误，意外''SELECT * FROM members WHERE e'（T_CONSTANT_ENCAPSED_STRING）

5 个答案: