Question

我有一个字符串"105,1,13312;105,2,13314;105,3,13316;106,1,13318;106,2,13320;106,3,13322"

我需要将字符串转换为列表

List<MyClass> registers = new List<MyClass>();

class MyClass{
        public int TOT_ID;
        public int phaze;
        public int register;
    }

我试过

registers = registersArr.Split(';')
               .Select(x => x.Split(','))
               .Where(x => x.Length == 3)
               .ToList(x => x[0], x => x[1], x=> x[2]);

我收到错误

Error   191 'System.Array' does not contain a definition for 'Select' and no extension method 'Select' accepting a first argument of type 'System.Array' could be found (are you missing a using directive or an assembly reference?)

Answer 1

你可能忘记了

using System.Linq;

然后：

registers = registersArr.Split(';')
                        .Select(x => x.Split(','))
                        .Where(x => x.Length == 3)

从这里改变：

                        .Select(x => new MyClass 
                               { 
                                    TOT_ID = int.Parse(x[0]), 
                                    phaze = int.Parse(x[1]), 
                                    register = int.Parse(x[2]) 
                               })
                        .ToList();

Answer 2

试试此代码

 string s = "105,1,13312;105,2,13314;105,3,13316;106,1,13318;106,2,13320;106,3,13322";
        List<MyClass> registers = new List<MyClass>();
        registers = s.Split(';')
            .Select(x => new MyClass() {
                TOT_ID = x[0], 
                phaze = x[1],
                register =x[2] 
            }).ToList();

Answer 3

这对我有用：

registers = registersArr.Split（＆＃39 ;;＆＃39;） .Select（x =＆gt; new MyClass {TOT_ID = int.Parse（x.Split（＆＃39;，＆＃39;）[0]），phaze = int.Parse（x.Split（＆＃39;，＆＃39;）[1]），register = int.Parse（x.Split（＆＃39;，＆＃39;）[2]）}） .ToList（）;

如何将字符串拆分为对象列表

3 个答案: