Question

在我使用flask-migrate和Alembic的烧瓶应用程序中，我得到了这个URL＆＃34; /用户/ 1排序= ascmonkey = LT？; flask_sqlalchemy.Pagination + object + at + 0x7f6a8077ea10＆gt;＆＃34 ;,而这部分是额外的＆lt; flask_sqlalchemy.Pagination + object + at + 0x7f6a8077ea10＆gt;它来自哪里，如何摆脱它？Thanx

View.py：

@layout.route('/user/<int:page>', methods = ['GET', 'POST'])
def user(page=1, sort='normal'):
    user = g.user
    #condition to sort base on ascending
    if request.args.get('sort') =='asc':
            sortBy = 'asc'
            monkey = Users.query.order_by(Users.name.asc()).paginate(page, MONKEYS_PAGE)
MONKEYS_PAGE)
 return render_template('Users.html',
            user = user,
            title ='Home',
            monkey = monkey,
            sortBy = sortBy
            )

User.html

   <div class="text-right sortby">
   <span>Sort by</span>
   <a href="{{ url_for('layout.user', page = '1', sort = 'asc', monkey = monkey) }}" class="btn btn-default btn-xs">
     <span class="glyphicon glyphicon-sort-by-alphabet"></span>
     name
   </a>

   <a href="{{ url_for('layout.user', page = '1', sort = 'friendnum', monkey = monkey) }}" class="btn btn-default btn-xs">
     <span class="glyphicon glyphicon-link"></span>
     number of friends
   </a>
   <a href="{{ url_for('layout.user', page = '1', sort = 'bf', monkey = monkey) }}" class="btn btn-default btn-xs">
     <span class="glyphicon glyphicon-link"></span>
     name of best friends
   </a>
 </div>

Answer 1

monkey是一个分页的用户列表，基于您显示的查询。实际用户存储在monkey.items列表中。根据您显示的内容，您要么迭代这些项目以生成单个网址，要么您希望monkey成为一个用户而不是分页列表。现在你正在做url_for('user', monkey=monkey)行，所以Flask将分页对象的字符串表示放入查询参数中。

我从网址获取的<flask_sqlalchemy.pagination + object + at + 0x7f6a87687950> </flask_sqlalchemy.pagination+object+at+0x7f6a87687950>

1 个答案: