我的CMS生成下一个代码:
<table class="variations" cellspacing="0">
<tbody>
<tr>
<td class="label">
<label for="pa_period">period</label>
</td>
<td class="value">
<fieldset>
<strong>Choose An Option...</strong><br />
<input type="radio" value="today" id="pa_period" name="attribute_pa_period">today<br />
<input type="radio" value="tomorrow" id="pa_period" name="attribute_pa_period">tomorrow<br />
</fieldset>
</td>
</tr>
<tr>
<td class="label">
<label for="pa_version">version</label>
</td>
<td class="value">
<fieldset>
<strong>Choose An Option...</strong><br />
<input type="radio" value="inoffice" id="pa_version" name="attribute_pa_version">in office<br />
<input type="radio" value="bymail" id="pa_version" name="attribute_pa_version">by mail<br />
</fieldset>
</td>
</tr>
</tbody>
</table>
正如您所看到的,此输出不包含代码&#39;标签&#39;输入后的文字。 我尝试过使用代码
$('fieldset strong').remove();
$('fieldset br').remove();
$('label').remove();
var text = $.trim($('fieldset').text());
var te = text.split("\n");
$('fieldset :radio, fieldset :checkbox').each(function (i) {
$(this).after('<label for="' + this.id + '">' + te[i] + '</label>');
});
var child = $('fieldset').children('input,label');
$('fieldset').html(child);
但是这个鳕鱼不起作用(我在jquery中是新的)
已编辑...感谢@charlietfl。 我的Woocommerce Radio Buttons Plugin(https://wordpress.org/plugins/woocommerce-radio-buttons/)
的结果代码$(document).ready(function() {
$('fieldset strong').remove();
$('fieldset br').remove();
var $nodes = $('fieldset').contents();
$nodes.each(function (i) {
if ($(this).is('input')) {
this.id = this.id+i;
var nextNode = $nodes[i + 1];
if (nextNode && nextNode.nodeType == 3) {
var label = '<label for="' + this.id + '">' + nextNode.textContent + '</label>';
$(nextNode).replaceWith(label);
}
}
});
});
答案 0 :(得分:0)
您的文字数组不是您所期望的
["today", " ",
" tomorrow",
" ",
" ",
"", " ",
" in office",
" ",
" by mail"]
您可以使用
te=te.filter(function(str){
return $.trim(str)!="";
});
$('fieldset strong').remove();
$('fieldset br').remove();
$('label').remove();
var text = $.trim($('fieldset').text());
var te = text.split("\n");
te=te.filter(function(str){
return $.trim(str)!="";
});
$('fieldset :radio, fieldset :checkbox').each(function (i) {
$(this).after('<label for="' + this.id + '">' + te[i] + '</label>');
});
var child = $('fieldset').children('input,label');
$('fieldset').html(child);
&#13;
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script>
<table class="variations" cellspacing="0">
<tbody>
<tr>
<td class="label">
<label for="pa_period">period</label>
</td>
<td class="value">
<fieldset> <strong>Choose An Option...</strong>
<br />
<input type="radio" value="today" id="pa_period" name="attribute_pa_period" />today
<br />
<input type="radio" value="tomorrow" id="pa_period" name="attribute_pa_period" />tomorrow
<br />
</fieldset>
</td>
</tr>
<tr>
<td class="label">
<label for="pa_version">version</label>
</td>
<td class="value">
<fieldset> <strong>Choose An Option...</strong>
<br />
<input type="radio" value="inoffice" id="pa_version" name="attribute_pa_version">in office
<br />
<input type="radio" value="bymail" id="pa_version" name="attribute_pa_version">by mail
<br />
</fieldset>
</td>
</tr>
</tbody>
</table>
&#13;
答案 1 :(得分:0)
这是一种使用contents()
的方法,因此您可以检查跟随输入的文本节点并仅替换那些文本节点
var $nodes = $('fieldset').contents();
$nodes.each(function (i) {
if ($(this).is('input')) {
var nextNode = $nodes[i + 1];
if (nextNode && nextNode.nodeType == 3) {
var label = '<label for="' + this.id + '">' + nextNode.textContent + '</label>';
$(nextNode).replaceWith(label);
}
}
});
您还可以使用input
修改textarea
选择器以包含select
和:input
的 DEMO 强>