Question

这个JavaScript如何生成角色？我想制作PHP版本。

这是打包的JavaScript代码

(function(options, lary) {
eval((function(g6) {
    for (var R6 = "", c6 = 0, Q6 = function(g6, C6) {
            for (var G6 = 0, x6 = 0; x6 < C6; x6++) {
                G6 *= 96;
                var r6 = g6.charCodeAt(x6);
                if (r6 >= 32 && r6 <= 127) {
                    G6 += r6 - 32;
                }
            }
            return G6;
        }; c6 < g6.length;) {
        if (g6.charAt(c6) != "`") R6 += g6.charAt(c6++);
        else {
            if (g6.charAt(c6 + 1) != "`") {
                var o6 = Q6(g6.charAt(c6 + 3), 1) + 5;
                R6 += R6.substr(R6.length - Q6(g6.substr(c6 + 1, 2), 2) - o6, o6);
                c6 += 4;
            } else {
                R6 += "`";
                c6 += 2;
            }
        }
    }
    return R6;
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我试图在此网站上解压缩此代码http://www.strictly-software.com/unpack-javascript 但我真的不知道那是什么。

此JavaScript生成随机51个字符。像这样：6645a0e75cce8b7bbf315603373dce3c6119750240024580738

那么，我如何用PHP生成随机的51个字符？你能帮我搞简单的PHP代码吗？

谢谢senpai ^^

Answer 1

这样的东西？

$rand = substr(md5(microtime()),rand(0,26),51);

Answer 2

你想要返回1个字符串，或51个单独的字符？对于1个字符串，您可以执行以下操作：

function randomString($length = 51) {
    $str = "";
    $characters = array_merge(range('A','Z'), range('a','z'), range('0','9'));
    $max = count($characters) - 1;
    for ($i = 0; $i < $length; $i++) {
        $rand = mt_rand(0, $max);
        $str .= $characters[$rand];
    }
    return $str;
}

这个JavaScript如何生成角色？

2 个答案: