Question

这是我的代码，我无法通过＆＃34;不是有效的选择＆＃34;在SelectField上，无论是创建形式还是编辑形式...我将其作为选择传递的类别是unicode，即便如此，我尝试了各种各样的＆＃34; coerce＆＃34; Form SelectField中的设置

class ProductsView(MyModelView):
create_template = '/admin/edit-products.html'
form = ProductForm

def create_form(self, model=None):
    form = self.form()
    choices = list(db.db.categories.find())
    choices.sort(key=lambda x: x['order'])
    sorted_choices = [(str(cat['name']), cat['name']) for cat in choices]
    print sorted_choices
    form.category.choices = sorted_choices
    if model:
        form.name.data = model['name']
        form.order.data = int(model['order'])
    return form

    def edit_form(self, obj):
    try:
        pk = self.get_pk_value(obj)
        if not pk:
            raise ValueError('Document does not have _id')
        model = db.db.products.find_one(pk)
        form = self.create_form(model)
        return form
    except Exception as ex:
        print ex
        flash(gettext('Failed to edit product. %(error)s', error=str(ex)),
              'error')

Answer 1

您可以创建自定义SelectField并覆盖pre_validate方法。像这样：

class MySelectField(SelectField):

def pre_validate(self, form):
    for v, _ in self.choices:
        if your validation:
            break
    else:
        raise ValueError(self.gettext('Not a valid choice'))

动态SelectField验证失败：“不是有效选择”

1 个答案: