Question

我有一个返回不同记录的SQL查询

select distinct 
VENDOR_NUMBER,VENDOR_NAME,CHECK_DATE,
EMAIL_ADDRESS,FAX,check_amount 
from MOF_AP_REMITTANCE_GFOS_HEADER_HISTORY 
where VENDOR_NUMBER = 4382501 and DATEPART(yy, CHECK_DATE) = '2015'



4382501 | Zayani | 2015-01-15 | xx@bb.com | NULL | 1460.000

4382501 | Zayani | 2015-01-29 | xx@bb.com | NULL | 5556.000

4382501 | Zayani | 2015-02-15 | xx@bb.com | NULL | **730.000**

4382501 | Zayani | 2015-02-15 | xx@bb.com | NULL | **11781.000**

如果我有多条记录，我需要得到每条记录的总和我需要结果看起来像下面的

4382501 | Zayani | 2015-01-15 | xx@bb.com | NULL | 1460.000

4382501 | Zayani | 2015-01-29 | xx@bb.com | NULL | 5556.000

4382501 | Zayani | 2015-02-15 | xx@bb.com | NULL | **12511.000**

我尝试使用SUM函数，但由于DB中的数据看起来像这样，我得到了错误的结果

4382501 | Zayani | 2015-01-15 | xx@bb.com | NULL | 1460.000
4382501 | Zayani | 2015-01-15 | xx@bb.com | NULL | 1460.000
4382501 | Zayani | 2015-01-29 | xx@bb.com | NULL | 5556.000
4382501 | Zayani | 2015-02-15 | xx@bb.com | NULL | **730.000**
4382501 | Zayani | 2015-02-15 | xx@bb.com | NULL | **11781.000**

如果你能看到第二条记录是重复的那就是为什么我使用了不同的

任何建议？

Answer 1

使用GROUP BY和SUM：

select VENDOR_NUMBER,VENDOR_NAME,CHECK_DATE,
       EMAIL_ADDRESS,FAX,SUM(check_amount ) as check_amount 
from (select distinct 
             VENDOR_NUMBER,VENDOR_NAME,CHECK_DATE,
             EMAIL_ADDRESS,FAX,check_amount 
      from MOF_AP_REMITTANCE_GFOS_HEADER_HISTORY 
      where VENDOR_NUMBER = 4382501 and DATEPART(yy, CHECK_DATE) = '2015'))
GROUP BY VENDOR_NUMBER,VENDOR_NAME,CHECK_DATE,EMAIL_ADDRESS,FAX

如何获得不同记录的总和

1 个答案: