我通过在表上声明两个外键来面对一个奇怪的问题,这也是我表中的主键。这是我的sql代码:
CREATE TABLE IF NOT EXISTS guest (
id_guest varchar(50) NOT NULL,
PRIMARY KEY(id_guest)
) ENGINE=InnoDb DEFAULT CHARSET=latin1;
CREATE TABLE IF NOT EXISTS product (
id_product varchar(100) NOT NULL,
PRIMARY KEY(id_product)
) ENGINE=InnoDb DEFAULT CHARSET=latin1;
CREATE TABLE IF NOT EXISTS product_guest_resale (
id_guest varchar(50) NOT NULL,
id_product varchar(100) NOT NULL,
amount int(100) NOT NULL,
PRIMARY KEY (id_guest, id_product),
FOREIGN KEY id_guest REFERENCES guest(id_guest),
FOREIGN KEY id_product REFERENCES product(id_product)
) ENGINE=InnoDb DEFAULT CHARSET=latin1;
当我执行我的代码时,我得到了这个错误:
#1064 - You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'REFERENCES guest(id_guest),
FOREIGN KEY id_product REFERENCES product(' at line 6
出了什么问题?
答案 0 :(得分:1)
你错过了括号:
CREATE TABLE IF NOT EXISTS product_guest_resale (
id_guest varchar(50) NOT NULL,
id_product varchar(100) NOT NULL,
amount int(100) NOT NULL,
PRIMARY KEY (id_guest, id_product),
FOREIGN KEY (id_guest) REFERENCES guest(id_guest),
FOREIGN KEY (id_product) REFERENCES product(id_product)
) ENGINE=InnoDb DEFAULT CHARSET=latin1;