Question

我下面有一些JSON。之前我在JSON响应中只有items元素，并且使用改进来使用以下代码访问它。哪个工作正常。

但是现在我添加了推荐部分，我已经创建了推荐模型，但是现在如何从响应的推荐/项目部分访问数据？

修改也许有更好的方法可以返回这些数据。可能有500个项目，但只有20/30个列表，所以我认为拆分而不是复制数据会更好。

JSON

[
{
    "recommendation": [
        {
            "following": true,
            "list_id": "29",
            "list_name": "list29",
        },
        {
            "following": false,
            "list_id": "28",
            "list_name": "list28",
        }
    ]
},
{
    "items": [
        {
            "description": [
                "line1",
                "line2",
                "line3"
            ],
            "image1": "4367218/img1.jpg",
            "item_id": 5600,
            "title": "Title 1",
            "recommendation_id": 29
        },
        {
            "description": [
                "line1",
                "line2",
                "line3"
            ],
            "image1": "342345/img1.jpg",
            "item_id": 3600,
            "title": "Tite2",
            "recommendation_id": 28
        }
    ]
}
]

推荐模型

public class Recommendation {

    private Boolean following;
    private int listId;
    private String listName;

    public Boolean getFollowing() {
        return following;
    }

    // more getters and setters
}

项目模型

public class Item {

    private int item_id;
    private String title;
    private ArrayList<String> description;
    private String image1;
    private int recommendation_id;

    // more getters and setters
}

改进GET

// feed
@GET("/items/{user_id}/{num_items}")
public void getFeedData(@Path("user_id") int user_id, @Path("num_items") Integer num_items, Callback<List<Item>> response);

Answer 1

{
    "recommendation": [
        "data":{
            "following": true,
            "list_id": "29",
            "list_name": "list29"
        },
       "data": {
            "following": false,
            "list_id": "28",
            "list_name": "list28"
        }
    ]
},
{
    "items": [
        "data_item":{
            "description": [
                "line1",
                "line2",
                "line3"
            ],
            "image1": "4367218/img1.jpg",
            "item_id": 5600,
            "title": "Title 1",
            "recommendation_id": 29
        },
         "data_item":{
            "description": [
                "line1",
                "line2",
                "line3"
            ],
            "image1": "342345/img1.jpg",
            "item_id": 3600,
            "title": "Tite2",
            "recommendation_id": 28
        }
    ]
}

型号：

public class Model{

ArrayList<Data> recommendation ; 
ArrayList<DataItem> items ;
}

数据模型：

public class Data{

   private boolean following ;
   private String list_id ;
   private String list_name ;

}

DataItem Model：

public class DataItem{

private String description [];
private String image1 ;
private String item_id ;
private String title ;
private String recommendation_id ;

}

Answer 2

我建议将JSON根目录从数组转换为object：

{
    "recommendation": [...],
    "items": [...]
}

然后让Retrofit将JSON响应解析为新模型，假设为Response：

public class Response {
    private Recommendation[] recommendation;
    private Item[] items;
    // your getters
}

在Json响应中改进访问多个模型

2 个答案: