从自定义函数返回一个promise

Question

^原帖GitHub

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您好，

您能告诉我如何使用蓝鸟从自定义函数返回承诺吗？以下是我正在使用的内容：

var session = require('express-session');
var RedisStore = require('connect-redis')(session);
var P = require('bluebird');

var redisSessionStore = new RedisStore({client: redisClient});
P.promisifyAll(redisSessionStore);

redisSessionStore.getAsync('active_session').then(function(data) {  
    if(!data || (data.timestamp < Data.now())) {
        return sulogin(params);
    }
}).then(function(values) { // expecting sulogin to return a promise
  // do another async call
});

function sulogin(params){

}

如何让sulogin回复承诺？

Answer 1

我修改了sulogin看起来像这样：

var http = require('http');
var Promise = require('bluebird');

function sulogin(arg, fn) {
    Promise.props({
        host:"localhost",
        port: 8080,
        path: '/uaa/login.do',
        method: 'POST',
        headers: {'Content-Type': 'application/x-www-form-urlencoded'}
    }).then(function(result) {
        return http.requestAsync(result);
    });
}

感谢https://github.com/petkaantonov/bluebird/issues/196