这是命令行CURL代码: -
curl -X POST "http://{$HOST}/api/1/videos.json" \
-H "Content-type: application/json" \
-H "X-Reseller-Email: $RESELLER" \
-H "X-Reseller-Token: $TOKEN" \
-H "X-User-Email: $USER" \
-d '{"video":{
"title": "My video from API",
"description": "Description from API",
"video_template_id": "16",
"track_id": "26",
"texts": [
{
"layer": "VLN_txt_01",
"value": "My text 1"
}
],
"images": [
{
"layer": "VLN_icon_01",
"source": "icon",
"icon_id": "1593"
}
]
}}'
请帮我转换成PHP CURL调用。此外,我需要使用POST和PUT方法进行此调用。我已经创建了但是无法在PHP中转换数据有效负载。
我只需要知道我怎样才能写出" -d" PHP中的(数据)与PHP中的命令行CURL调用相同。
答案 0 :(得分:1)
您必须与CURLOPT_POSTFIELDS
结合使用CURLOPT_HTTPHEADER
选项。 CURLOPT_POSTFIELDS
选项必须设置为JSON字符串,CURLOPT_HTTPHEADER
- 包含所有必需HTTP标头的数组(包括Content-type
)。
所以代码应如下所示:
$json = '{"video":{
"title": "My video from API",
"description": "Description from API",
"video_template_id": "16",
"track_id": "26",
"texts": [
{
"layer": "VLN_txt_01",
"value": "My text 1"
}
],
"images": [
{
"layer": "VLN_icon_01",
"source": "icon",
"icon_id": "1593"
}
]
}}';
$ch = curl_init();
curl_setopt_array($ch, array(
CURLOPT_URL => "http://{$HOST}/api/1/videos.json",
CURLOPT_NOBODY => false,
CURLOPT_RETURNTRANSFER => true,
CURLOPT_POST => true,
CURLOPT_POSTFIELDS => $json,
CURLOPT_HTTPHEADER => array(
"Content-type: application/json",
"X-Reseller-Email: $RESELLER",
"X-Reseller-Token: $TOKEN",
"X-User-Email: $USER",
),
));
$response = curl_exec($ch);
if ($response && curl_getinfo($ch, CURLINFO_HTTP_CODE) == 200)
echo $response;