好的,所以请不要太激怒我,这是我的第一个问题,也许我想做的事情甚至不可能。显然我不是专家;这就是我要来找你的原因。 :)
我在这里搜索过,MSDN和其他互联网(其中大部分都指向这里)没有任何运气。我确实看到一个问题,询问使用OpenFileDialog
选择文件夹而不是文件。我几乎可以肯定,我已经在主流应用程序中看到了这个问题,但这个问题被标记为过于含糊,而且在回复中没有得到解决。
我有一些需要文件/文件夹路径的文本框。我想简化处理这个问题的两种方法。唯一的区别是,一旦选择一个文件,另一个选择一个文件夹。为了简单和可读性,我想整合它们。
这是否可行,而不是将每个代码方法的内容放入一个大的IF
?
以下是两种方法:
private void FolderBrowser(object sender, EventArgs e)
{
TextBox SenderBox = sender as TextBox;
if (SenderBox.Text != "")//if the text box is not empty
{
//set the selected path to the text box's current contents (incase of accidental entry)
FileBrowserDialog.FileName = SenderBox.Text;
}
if (FileBrowserDialog.ShowDialog() == DialogResult.OK)
{
SenderBox.Text = FileBrowserDialog.FileName;
}
}
private void FileBrowser(object sender, EventArgs e)
{ //basically the same as the folder browser above, but for selecting specific files
TextBox SenderBox = sender as TextBox;
if (SenderBox.Text != "")//if the text box is not empty
{
//set the selected path to the text box's current contents (incase of accidental entry)
FileBrowserDialog.FileName = SenderBox.Text;
}
if (FileBrowserDialog.ShowDialog() == DialogResult.OK)
{
SenderBox.Text = FileBrowserDialog.FileName;
}
}
我已为每个Tag
添加了TextBox
,表明它是否需要文件或文件夹。我想使用Tag
作为判断我是否应该使用文件或文件夹浏览器的条件。这是我无知所表现的地方;我曾设想过像这样的非工作代码:
private void browser(object sender, EventArgs e)
{
//cast sender as a textbox
TextBox tBox = (TextBox)sender;
object browser = null;
if (tBox.Tag.ToString().Equals("Folder"))
{
browser = new FolderBrowserDialog();
}
else
{
browser = new OpenFileDialog();
}
if (tBox.Text != "")//if the text box is not empty
{
//set the selected path to the text box's current contents (incase of accidental entry)
browser.FileName = tBox.Text;
}
if (browser.ShowDialog() == DialogResult.OK)
{
tBox.Text = browser.FileName;
}
}
我疯了,还是有办法实现我的想法?要清楚,我想知道是否有:
OpenFileDialog
动态允许使用FileBrowserDialog
或Tag
的任何其他方法。答案 0 :(得分:0)
尝试使用FolderBrowserDialogEx。
在这里查看详细解答: How do you configure an OpenFileDialog to select folders?
答案 1 :(得分:0)
这是我在不依赖第三方代码的情况下解决此问题的最简单方法,但您需要添加一些完整性检查,以防用户使用输入:
OpenFileDialog ofd = new OpenFileDialog();
ofd.CheckFileExists = false;
string defaultFilename = "Select this folder";
ofd.FileName = defaultFilename;
if (ofd.ShowDialog().Value)
{
// Check if the user picked a file or a directory, for example:
if (!ofd.FileName.Contains(defaultFilename))
{
// File code
}
else // You should probably turn this into an else if instead
{
// Directory code
}
// Alternatively, but still as unsafe
if (File.Exists(ofd.FileName))
{
// File code
}
else
{
// Directory code
}
}
基本上,"技巧"这里是将OpenFileDialog的CheckFileExists设置为false。
答案 2 :(得分:0)
两个对话框(FileOpenDialog
和FolderBrowserDialog
)都继承自CommonDialog
;但是,此基类没有用于检索结果的属性。此外,两个对话框中的属性命名都不同。
您可以通过创建包装器来解决问题。继承是将对象重新定义为不同类型的正确方法。
public abstract class FileFolderDialogBase
{
public abstract bool ShowDialog();
public string Result { get; protected set; }
}
public class FileDialog : FileFolderDialogBase
{
public override bool ShowDialog()
{
var ofd = new OpenFileDialog();
if ofd.ShowDialog() == DialogResult.OK) {
Result = ofd.FileName;
return true;
}
return false;
}
}
public class FolderDialog : FileFolderDialogBase
{
public override bool ShowDialog()
{
var fbd = new FolderBrowserDialog();
if (fbd.ShowDialog() == DialogResult.OK)
Result = fbd.SelectedPath;
return true;
}
return false;
}
}
用法:
var dialog = textBox.Tag == "Folder" ? new FolderDialog() : new FileDialog;
if (dialog.ShowDialog()) {
textBox.Text = dialog.Result;
}
您可以通过创建工厂类
来进一步推动它public static class FileFolderDialog
{
public static FileFolderDialogBase Create(string type)
{
swich (type.ToLowerInvariant()) {
case "folder":
case "dir":
case "directory":
return new FolderDialog();
default:
return new FileDialog();
}
}
}
用法
var dialog = FileFolderDialog.Create(textBox.Tag);
if (dialog.ShowDialog()) {
textBox.Text = dialog.Result;
}
答案 3 :(得分:0)
为什么不尝试扩展TextBox类? 它很简单且可重复使用,您只需要将自定义控件拖放到WinForm
class FileTextBox : System.Windows.Form.TextBox{
//===>This enumeration is more readable insted of a string XD
public enum DialogType{
File,Folder
}
//===>This property we will handle what kind of Dialog to show
public DialogType OpenDialogType{
get;
set;
}
//===>This is where Object Oriented Programming a& Design do his magic
public System.Windows.Forms.DialogResult ShowDialog(string Title =""){
//===>This function is where we define what kind of dialog to show
System.Windows.Forms.DialogResult Result = System.Windows.Forms.DialogResult.None ;
object Browser=null;
switch(this.OpenDialogType){
case DialogType.File:
Browser = new OpenFileDialog();
((Browser)OpenFileDialog).Title= Title;
if(this.Text.Trim() !="" && this.Text != null ){
((Browser)OpenFileDialog).FileName = this.Tex;
}
Result = ((Browser)OpenFileDialog).ShowDialog();
break;
case DialogType.Folder:
Browser = new FolderBrowserDialog ();
((Browser)FolderBrowserDialog).Description = Title;
if(this.Text.Trim() !="" && this.Text != null ){
((Browser)FolderBrowserDialog).RootFolder = this.Text;
}
Result = ((Browser)FolderBrowserDialog).ShowDialog();
break;
}
return Result;//===>We return thi dialog result just if we want to do something else
}
}
/*
Create a class and copy/paste this code, I think is going to work because
I didn't compiled then go to ToolBox window find this control and Drag & Drop
to your WinForm and in the property window find OpenDialogType property
and this is where you kind define the behavior of OpenDialog();
I'm currently working in a little project in Vs where I create a custom
UI Control downloaded from my git repository
https://github.com/MrAlex6204/GYMSystem
*/