我的Django项目中有多个模型表单,并希望为所有表单添加三个字段。
但是当我编写一个简单的表单然后将其子类化时,我会收到错误。
class PersonForm(forms.Form):
person_name = forms.CharField(
label=u'Entregado por',
max_length=64,
)
person_document_number = forms.CharField(
label=u'Número de Documento',
max_length=15,
)
person_document_type = forms.ChoiceField(
label=u'Tipo de Documento',
choices=BLANK_CHOICE_DASH + list(DOCUMENT_TYPE_CHOICES),
)
class ContractForm(PersonForm, forms.ModelForm):
class Meta:
model = Contract
def __init__(self, *args, **kwargs):
super(ContractForm, self).__init__(*args, **kwargs)
self.fields['person_name'].widget.attrs['class'] = 'js-person-name'
错误:
TypeError: Error when calling the metaclass bases
metaclass conflict: the metaclass of a derived class must be a (non-strict) subclass of the metaclasses of all its bases
我尝试定义PersonForm
之类的
class PersonForm:
person_name = forms.CharField(
label=u'Entregado por',
max_length=64,
)
# ....
没有从forms.Form
继承,并收到错误:
django.core.exceptions.FieldError: Unknown field(s) (person_document_type, person_document_number, person_name) specified for Contract
有没有漂亮的方法(不将这些字段复制到我的所有模型表格中)?
答案 0 :(得分:3)
为什么不用ModelForm实现PersonForm?
class PersonForm(forms.ModelForm):
person_name = forms.CharField(
label=u'Entregado por',
max_length=64,
)
person_document_number = forms.CharField(
label=u'Número de Documento',
max_length=15,
)
person_document_type = forms.ChoiceField(
label=u'Tipo de Documento',
choices=BLANK_CHOICE_DASH + list(DOCUMENT_TYPE_CHOICES),
)
class ContractForm(PersonForm):
class Meta:
model = Contract
def __init__(self, *args, **kwargs):
super(ContractForm, self).__init__(*args, **kwargs)
self.fields['person_name'].widget.attrs['class'] = 'js-person-name'