Question

我正在使用v2 AWS iOS SDK将我的图像上传到服务器我的代码我是前进的

 NSString * uniqueIdentifier = [[NSUUID UUID]UUIDString];

AWSS3TransferManagerUploadRequest *uploadRequest = [AWSS3TransferManagerUploadRequest new];
uploadRequest.bucket = @"my bucket";
uploadRequest.key = [NSString stringWithFormat:@"%@/images/%@.jpeg",objectId,uniqueIdentifier];
uploadRequest.ACL = AWSS3ObjectCannedACLPublicRead;

NSData * data = UIImageJPEGRepresentation(newImage, 0.8);

NSString *tmpDirectory = NSTemporaryDirectory();

NSString *tmpFile = [tmpDirectory stringByAppendingPathComponent:[NSString stringWithFormat:@"%@.jpeg",uniqueIdentifier]];
NSLog(@"Temp File:%@", tmpFile);

[data writeToFile:tmpFile atomically:YES];

uploadRequest.body = [NSURL fileURLWithPath:tmpFile];

AWSS3TransferManager *transferManager = [AWSS3TransferManager defaultS3TransferManager];

[[transferManager upload:uploadRequest] continueWithExecutor:[BFExecutor defaultExecutor]
                                                   withBlock:^id(BFTask *task) {
                                                       if (task.error != nil) {
                                                           NSLog(@"%s %@","Error uploading :", uploadRequest.key);
                                                       }else {

                                                           AWSS3TransferManagerUploadOutput * output = task.result;


                                                           NSLog(@"Upload completed %@",[output description]);


                                                       }
                                                       return nil;
                                                   }];

将文件上传到S3服务后，响应URL在哪里？我怎么知道那张图片的网址？我想通过DB将图像放在一个对象中。

感谢

Answer 1

可公开阅读的Amazon S3对象遵循以下URL模式：

https://S3Endpoint/BucketName/ObjectName

查找对象网址的最简单方法是转到对象“链接：”的AWS Management Console和look。

AWSS3TransferManagerUploadRequest获取响应URL

1 个答案: