我正在使用名为star.xml的XML文件创建一个应用程序,以将我的数据存储在列表视图中。我是c#和编程的新手,需要任何帮助 基本上,我希望能够输入我的搜索文本框(称为“搜索”)和我的列表视图(lstStar)以仅显示匹配的记录。即输入'Audi'只会返回这些项目。 任何帮助都感激不尽 仁
namespace StarinCar
{
public partial class MainWindow : Window
{
int hot = -2;
int Mildly_Moist = -2;
int Wet = -4;
int Very_Wet = -6;
private ObservableCollection<star> starData;
public MainWindow()
{
InitializeComponent();
starData = new ObservableCollection<star>();
lstStar.ItemsSource = starData;
try
{
XmlSerializer xs = new XmlSerializer(typeof(ObservableCollection<star>));
using (StreamReader rd = new StreamReader("star.xml"))
{
starData = xs.Deserialize(rd) as ObservableCollection<star>;
}
}
catch
{
}
lstStar.ItemsSource = starData;
lblAverage.Content = starData.Average(i => i.time).ToString();
lblFastest.Content = starData.Min(i => i.time).ToString();
lblSlowest.Content = starData.Max(i => i.time).ToString();
}
private void btnAdd_Click(object sender, RoutedEventArgs e)
{
star newStar = new star();
newStar.firstName = txtName.Text;
newStar.time = int.Parse(txtTime.Text);
newStar.car = txtCar.Text;
newStar.track = txtTrack.Text;
starData.Add(newStar);
if (txtTrack.Text.Contains("Hot") || (txtTrack.Text.Contains("hot") == true))
{
newStar.time = int.Parse(txtTime.Text) + hot;
}
if (txtTrack.Text.Contains("Mildly Moist") || (txtTrack.Text.Contains("mildly moist")) == true)
{
newStar.time = int.Parse(txtTime.Text) + Mildly_Moist;
}
if (txtTrack.Text.Contains("Wet") || (txtTrack.Text.Contains("wet") == true))
{
newStar.time = int.Parse(txtTime.Text) + Wet;
}
if (txtTrack.Text.Contains("Very Wet") || (txtTrack.Text.Contains("very wet")) == true)
{
newStar.time = int.Parse(txtTime.Text) + Very_Wet;
}
}
private void Window_Closed(object sender, EventArgs e)
{
XmlSerializer xs = new XmlSerializer(typeof(ObservableCollection<star>));
using (StreamWriter wr = new StreamWriter("star.xml"))
{
xs.Serialize(wr, starData);
}
}
}
}
答案 0 :(得分:0)
您可以使用ICollectionView。所以你会得到你的“整体” 明星集合'starData'。但是你的listbox itemssource将绑定到这样的东西:
public ICollectionView FilteredStars
{
get
{
ICollectionView source = CollectionViewSource.GetDefaultView(starData);
source.Filter = new Predicate<object>(FilterStars);
return source;
}
}
这里进行过滤的逻辑:
private bool FilterStars(object item)
{
bool b = false;
star a = item as star;
if (a != null)
{
if (a.Name.Contains(searchBoxText)) //your filter logic here
{
b = true;
}
else if String.IsNullOrWhiteSpace(searchBoxText)
{
b = true;
}
}
return b;
}
基本上,你有你的主集合,然后是一些过滤你的主集合到过滤集合的逻辑,这就是你应该将列表框的itemssource设置为。到目前为止,这是假设您要在搜索文本框中添加某种属性更改,然后单击按钮,如“搜索”,然后告诉列表检查并重新填充以匹配搜索项。
答案 1 :(得分:-1)
这是我在类似应用程序中过滤的方式
public IEnumerable<string> PastEntries1
{
get
{
if(string.IsNullOrEmpty(textValue))
{
return FieldDefString.PastEntries;
}
else
{
return FieldDefString.PastEntries.Where(x => x.StartsWith(textValue, StringComparison.OrdinalIgnoreCase));
}
}
}